Her uiat ue an to vote yes on the new p is a correct interpretation of this p-value? approximately 0.0672. at a sample would show at least as much evidence against the null hypothesis as 1.83 (the observed test statistic value)

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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A large union is preparing to vote on a new contract. A random sample of 500 employees yields 320 who plan to vote yes on the new contract. Can we infer that the new contract will receive a different percentage "yes" votes than
60%? The test statistic for this test is z = 1.83. The corresponding p-value is 0.0672. Which of the following is a correct interpretation of this p-value?
O a. The probability that the null hypothesis is true is 0.0672
O b. The probability of concluding that the proportion who plan to vote yes is 0.60, when in fact it is not, is approximately 0.0672.
O. The probability that z = 1.83 if the null hypothesis is true equals 0.0672.
O d. If, in fact, the proportion who plan to vote yes is 0.60 (i.e. the null hypothesis is true), the probability that a sample would show at least as much evidence against the null hypothesis as 1.83 (the observed test statistic value)
equals 0.0672
Transcribed Image Text:A large union is preparing to vote on a new contract. A random sample of 500 employees yields 320 who plan to vote yes on the new contract. Can we infer that the new contract will receive a different percentage "yes" votes than 60%? The test statistic for this test is z = 1.83. The corresponding p-value is 0.0672. Which of the following is a correct interpretation of this p-value? O a. The probability that the null hypothesis is true is 0.0672 O b. The probability of concluding that the proportion who plan to vote yes is 0.60, when in fact it is not, is approximately 0.0672. O. The probability that z = 1.83 if the null hypothesis is true equals 0.0672. O d. If, in fact, the proportion who plan to vote yes is 0.60 (i.e. the null hypothesis is true), the probability that a sample would show at least as much evidence against the null hypothesis as 1.83 (the observed test statistic value) equals 0.0672
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