Hence, Ck obeys the difference equation - (1-* ). 7 3 Ck+1 Ck• (7.99) +... 2k 24k2 16k3

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Show me the steps of determine yellow

l stc ksa
9:49 PM
C 1 0 97% 4
Hence, cz obeys the difference equation
(1
1
3
Ck+1 =
Ck.
(7.99)
2k
24k2
16k3
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Transcribed Image Text:l stc ksa 9:49 PM C 1 0 97% 4 Hence, cz obeys the difference equation (1 1 3 Ck+1 = Ck. (7.99) 2k 24k2 16k3 Cancel Actual Size (375 KB) Choose
Higher-order correction may be obtained by using the representation
Ck =
(7.106)
where
A1
A2
+
k2
Аз
+....
k3
dk ~1+
(7.107)
k
Substitution of equation (7.106) into equation (7.99) gives
1
1
2k
1
7
dk+1
1+
24k2
+
16k3
dr
(7.108)
1
1
dr.
12k2
12k3
Note that no k
1
term appears in the k dependent function on the right side
of equation (7.108).
Let us now calculate the coefficient A1 in equation (7.107). To do this, we
substitute
A1
di
1+
ek
(7.109)
k
Transcribed Image Text:Higher-order correction may be obtained by using the representation Ck = (7.106) where A1 A2 + k2 Аз +.... k3 dk ~1+ (7.107) k Substitution of equation (7.106) into equation (7.99) gives 1 1 2k 1 7 dk+1 1+ 24k2 + 16k3 dr (7.108) 1 1 dr. 12k2 12k3 Note that no k 1 term appears in the k dependent function on the right side of equation (7.108). Let us now calculate the coefficient A1 in equation (7.107). To do this, we substitute A1 di 1+ ek (7.109) k
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