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Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve the 3D system by filling in the blanks correctly. Final anSwers must be supported by correct wwork. 1) 5z + 6y+ z = -2 2) 4z - 8y+ 6z = 6 3) 6z + 4y-6z = 8 Without doing any multiplying, I can combine equation 2 and v to eliminate the v when adding. This gives me equation 4, which is: 4) - 4y = v by Now I am going to combine equation 1 and equation 3. I will need to multiply Adding these together gives me equation 5, which is: 5) v to eliminate the y's. Now let's combine equation 4 and equation 5, but we will need to multiply equation 4 by
Transcribed Image Text:Solve the 3D system by filling in the blanks correctly. Final anSwers must be supported by correct wwork. 1) 5z + 6y+ z = -2 2) 4z - 8y+ 6z = 6 3) 6z + 4y-6z = 8 Without doing any multiplying, I can combine equation 2 and v to eliminate the v when adding. This gives me equation 4, which is: 4) - 4y = v by Now I am going to combine equation 1 and equation 3. I will need to multiply Adding these together gives me equation 5, which is: 5) v to eliminate the y's. Now let's combine equation 4 and equation 5, but we will need to multiply equation 4 by
This gives me equation 4, which is: 4) - 4y = Now I am going to combine equation 1 and equation 3. I will need to multiply by Adding these together gives me equation 5, which is: 5) v to eliminate the y's. Now let's combine equation 4 and equation 5, but we will need to multiply equation 4 by So and then z=1. Now we take the x, and substitute into either equation 4 or equation 5, whichever is easier. so y = -1. Finally, substituting the x and y into the easiest of the first 3 equations, I get z = -1.
Transcribed Image Text:This gives me equation 4, which is: 4) - 4y = Now I am going to combine equation 1 and equation 3. I will need to multiply by Adding these together gives me equation 5, which is: 5) v to eliminate the y's. Now let's combine equation 4 and equation 5, but we will need to multiply equation 4 by So and then z=1. Now we take the x, and substitute into either equation 4 or equation 5, whichever is easier. so y = -1. Finally, substituting the x and y into the easiest of the first 3 equations, I get z = -1.
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