Help understanding step 3. Can someone explain why I can't use Alternative step 3 instead of 3 since we have mass of ZnS produced. And why step 3 uses Zn's exten of reaction? Question: Calculate the theoretical yield of zinc sulphide, in grams, from the reaction of 0.5g zinc and 0.5g sulphur. If the actual yield is 0.6gZnS, what is the percentage yield? 8Zn+S →8ZnS = extent of 0.5(g) = 1.95 x 10 mol Step 3: Z Sn= Exv=9.56 x 10 molx c = 7.65 x 10 mol Alternative step 256.48_olx 1 m Mxv step 1: Z₁ = 0.5(g) 65.38_olx8 =9.56 x 10 mol Step 2: S= m m - raction= = v 3Z = 0.68 97.474 ol m

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
Help understanding step 3. Can someone explain why I can't use Alternative step 3 instead of 3 since we have mass of ZnS produced. And why step 3 uses Zn's exten of reaction? Question:
Calculate the theoretical yield of zinc sulphide, in grams, from the reaction of 0.5g zinc and 0.5g sulphur. If the actual yield is 0.6gZnS, what is the percentage yield? 8Zn +S → 8ZnS = extent of
8
-4
-3
-3
=
0.5(g)
= 9.56 x 10 mol Step 2: S
65.38ol x 8
0.5 (g)
=
= 1.95 x 10³ mol Step 3: Z¸S n = ¢ × v = 9.56 × 10 + mol x c = 7.65 x 10³ mol Alternative step
256.48 olx 1
n
m
m
n
raction = -=
V
3 Z =
n
m
Mxv
0.68
97.474 ol
m
step 1: Zn
=
Transcribed Image Text:Help understanding step 3. Can someone explain why I can't use Alternative step 3 instead of 3 since we have mass of ZnS produced. And why step 3 uses Zn's exten of reaction? Question: Calculate the theoretical yield of zinc sulphide, in grams, from the reaction of 0.5g zinc and 0.5g sulphur. If the actual yield is 0.6gZnS, what is the percentage yield? 8Zn +S → 8ZnS = extent of 8 -4 -3 -3 = 0.5(g) = 9.56 x 10 mol Step 2: S 65.38ol x 8 0.5 (g) = = 1.95 x 10³ mol Step 3: Z¸S n = ¢ × v = 9.56 × 10 + mol x c = 7.65 x 10³ mol Alternative step 256.48 olx 1 n m m n raction = -= V 3 Z = n m Mxv 0.68 97.474 ol m step 1: Zn =
Expert Solution
steps

Step by step

Solved in 4 steps with 7 images

Blurred answer
Knowledge Booster
Iodine Titrations
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY