(Help me with part 4) se the sample data and confidence level given below to complete parts​ (a) through​ (d).   A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll, n=919 and x=594 who said​ "yes." Use a 90% confidence level.   LOADING... Click the icon to view a table of z scores.       Question content area bottom Part 1 ​a) Find the best point estimate of the population proportion p.   0.6460.646 ​(Round to three decimal places as​ needed.) Part 2 ​b) Identify the value of the margin of error E.   E=0.0260.026 ​(Round to three decimal places as​ needed.) Part 3 ​c) Construct the confidence interval.   0.6200.620

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Author:Amos Gilat
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(Help me with part 4)
se the sample data and confidence level given below to complete parts​ (a) through​ (d).
 
A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,
n=919
and
x=594
who said​ "yes." Use a
90%
confidence level.
 
LOADING...
Click the icon to view a table of z scores.
 
 
 

Question content area bottom

Part 1
​a) Find the best point estimate of the population proportion p.
 
0.6460.646
​(Round to three decimal places as​ needed.)
Part 2
​b) Identify the value of the margin of error E.
 
E=0.0260.026
​(Round to three decimal places as​ needed.)
Part 3
​c) Construct the confidence interval.
 
0.6200.620<p<0.6720.672
​(Round to three decimal places as​ needed.)
Part 4
​d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below.
 
 
A.
One has
90​%
confidence that the sample proportion is equal to the population proportion.
 
B.
There is a
90​%
chance that the true value of the population proportion will fall between the lower bound and the upper bound.
 
C.
One has
90​%
confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.
 
D.
90​%
of sample proportions will fall between the lower bound and the upper bound.
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