Hello this is a really long question, but worth a shot at asking. copying and pasting it (based from 12.1 and 12.2): The times required for Speedy Lube to complete an oil change service on an automobile are normally distributed with a mean of 17 minutes and a standard deviation of 2.5 minutes. a. What is the probability that a randomly selected customer will wait longer than 20 minutes for an oil change? b. What is the probability that a randomly selected customer will wait between 15 and 20 minutes for an oil change? c. What is the probability that a randomly selected customer will wait less than 11 minutes for an oil change? d. Speedy Lube decides to offer half price oil changes for customers who have to wait too long for their service. If Speedy Lube does not want to give the discount to more than 3% of its customers, how long should it make the guaranteed time limit
Hello this is a really long question, but worth a shot at asking. copying and pasting it (based from 12.1 and 12.2):
The times required for Speedy Lube to complete an oil change service on an automobile are
a. What is the
b. What is the probability that a randomly selected customer will wait between 15 and 20 minutes for an oil change?
c. What is the probability that a randomly selected customer will wait less than 11 minutes for an oil change?
d. Speedy Lube decides to offer half price oil changes for customers who have to wait too long for their service. If Speedy Lube does not want to give the discount to more than 3% of its customers, how long should it make the guaranteed time limit
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