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Hello I want someone to answer this question as I have my doubts about this example question. I want to know how 50,000 Reynolds Number satisfies laminar conditions as a laminar flow would be of Reynolds number less than 2,000 and 50,000 is way above 2,000. Can you answer the question and explain how this satisfies the laminar conditions?

Hello I want someone to answer this question as I have my doubts about this example question. I want to know how 50,000 Reynolds Number satisfies laminar conditions as a laminar flow would be of Reynolds number less than 2,000 and 50,000 is way above 2,000. Can you answer the question and explain how this satisfies the laminar conditions?

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Hello I want someone to answer this question as I have my doubts about this example question. I want to know how 50,000 Reynolds Number satisfies laminar conditions as a laminar flow would be of Reynolds number less than 2,000 and 50,000 is way above 2,000. Can you answer the question and explain how this satisfies the laminar conditions?

Consider a water flow (20°C) at v = 0.1 m/s past a flat plate 1 m long. Compute the boundary layer thickness in the middle of the plate. Assume that the kinematic viscosity of water at 20°C is equal to 1x10-6 m²/s. The Reynolds number for the middle of the plate is equal to: ReL/2 = 0.1 [m/s] x 0.5 [m] / 1x10-6 [m²/s] = 50 000 This satisfies the laminar conditions. The boundary layer thickness is therefore equal to: 8≈ 5.0 x 0.5 / (50 000)¹/2 = 0.011 m
Transcribed Image Text:Consider a water flow (20°C) at v = 0.1 m/s past a flat plate 1 m long. Compute the boundary layer thickness in the middle of the plate. Assume that the kinematic viscosity of water at 20°C is equal to 1x10-6 m²/s. The Reynolds number for the middle of the plate is equal to: ReL/2 = 0.1 [m/s] x 0.5 [m] / 1x10-6 [m²/s] = 50 000 This satisfies the laminar conditions. The boundary layer thickness is therefore equal to: 8≈ 5.0 x 0.5 / (50 000)¹/2 = 0.011 m
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