Hello, I need help with this hw question. 2.Write a nested loop to print the following for any n x n image of odd dimensions: Example Output (if n==5): X 0 0 0 X X X X X X X 0 0 0 X X X X X X X 0 X 0 X Example Output (if n==3): X 0 X X X X X 0 X */ I was able to get the (if n==3) working but having trouble with getting the (if n==5) I have tried and just stuck. I have provided the code below. #include using namespace std; int main() { cout << endl; cout << "Example output for 5" << endl; for(int r=1; r<=5; ++r){ for(int c=1; c<=5; ++c){ if((r%1!=0 || c%1!=0 || r==c-1) && (r!=5 && c==5 || c==1)) // sorry for the vomit attempt cout << "x"; else cout << "o"; } cout << endl; } cout << endl; cout << "Example output for 3" << endl;//this I nailed for(int r=1; r<=3; r++){ for(int c=1; c<=3; c++){ if(r!=1 && r!=3 || c!=2) cout << "x"; else cout << "o"; } cout << endl; } cout << endl; return 0; }
Hello, I need help with this hw question.
2.Write a nested loop to print the following for any n x n image of odd dimensions:
Example Output (if n==5):
X 0 0 0 X
X X X X X
X 0 0 0 X
X X X X X
X 0 X 0 X
Example Output (if n==3):
X 0 X
X X X
X 0 X */
I was able to get the (if n==3) working but having trouble with getting the (if n==5) I have tried and just stuck. I have provided the code below.
#include <iostream>
using namespace std;
int main()
{
cout << endl;
cout << "Example output for 5" << endl;
for(int r=1; r<=5; ++r){
for(int c=1; c<=5; ++c){
if((r%1!=0 || c%1!=0 || r==c-1) && (r!=5 && c==5 || c==1)) // sorry for the vomit attempt
cout << "x";
else
cout << "o";
}
cout << endl;
}
cout << endl;
cout << "Example output for 3" << endl;//this I nailed
for(int r=1; r<=3; r++){
for(int c=1; c<=3; c++){
if(r!=1 && r!=3 || c!=2)
cout << "x";
else
cout << "o";
}
cout << endl;
}
cout << endl;
return 0;
}
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 3 images