Please Asap Hello, I have received your answer but I do not understand why 97K = 97C° can you please explain? Thanks a lot!During a 1st process, an ideal gas goes from a volume of 3.5 liters to 1.25 liters and itspressure goes from 32.0mmHg to 89.6mmHg. In a 2nd process, which follows the 1st, the gas volumedoubles and the pressure drops to 34.0mmHg.b) what is the number of degrees of freedom of the gas molecules?c) what was the total temperature change if initially it was 25C°?Answer: isothermal and adiabatic; 5; -72KYour answer:c) The total temperature change can be calculated using the ideal gas law, which relates the pressure,volume, temperature, and number of moles of a gas. For an isothermal process, the temperature isconstant, so we can use the ideal gas law to calculate the initial number of moles:n = RT32.0mmHgx3.5L.-0.0821Latlx298k= 0.471 molwhere R is the gas constant and T is the temperature in Kelvin.Using the same equation for the final state of the gas in the adiabatic process, we can find the finaltemperature:T₁ = P₁xV₁BXR34.0mmHg 2.5L= 0.471mal-0.0821Latol201KThe total temperature change is therefore:AT = Tf - Ti= 201K-298K=-97KHowever, we need to remember that the first process is isothermal, so the temperature does notchange during this process. Therefore, the temperature change for the second process is:AT Tf-Ti-201K-298K = -97KExplanation:However, we need to be careful when converting between Kelvin and Celsius scales, as theyhave different zero points. To find the change in Celsius from an initial temperature of 25°C, wesubtract the temperature in Celsius from the Kelvin temperature:AT = -97K= -97°C -25°C = -72"CTherefore, the total temperature change during the two processes is -72°C.

As you provide both question and answer and you have follow up doubts, so I am solving follow up…

Hello, I have received your answer but I do not understand why 97K = 97C° can you please explain? Thanks a lot! During a 1st process, an ideal gas goes from a volume of 3.5 liters to 1.25 liters and its pressure goes from 32.0mmHg to 89.6mmHg. In a 2nd process, which follows the 1st, the gas volume doubles and the pressure drops to 34.0mmHg. b) what is the number of degrees of freedom of the gas molecules? c) what was the total temperature change if initially it was 25C°? Answer: isothermal and adiabatic; 5; -72K Your answer:

Hello, I have received your answer but I do not understand why 97K = 97C° can you please explain? Thanks a lot! During a 1st process, an ideal gas goes from a volume of 3.5 liters to 1.25 liters and its pressure goes from 32.0mmHg to 89.6mmHg. In a 2nd process, which follows the 1st, the gas volume doubles and the pressure drops to 34.0mmHg. b) what is the number of degrees of freedom of the gas molecules? c) what was the total temperature change if initially it was 25C°? Answer: isothermal and adiabatic; 5; -72K Your answer:

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter19: Temperature, Thermal Expansion And Gas Laws

Section: Chapter Questions

Problem 76PQ

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