Helium gasi

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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Helium gas is compressed from 0.303 MPa and 275 K to 4.04 MPa and 300 K in a Claude refrigerator
utilizing a wet expander with a saturated-vapor compressor. Twenty percent of the compressed gas is
diverted through the main expander entering at 190 K and leaving at 0.303 MPa. The helium enters the
low temperature compressor at 0.101 MPa as saturated vapor and leaves at 0.303 MPa. If the
compressors, expanders and heat exchangers for this refrigerator are assumed to be ideal, determine
the refrigeration effect, coefficient of performance and figure of merit when no expander work is
recovered. The following thermodynamic properties are obtained from the
temperature--entropy
diagram for helium:
hl (0.303 MPa, 275 K) = 1444 kJj/kg
s1 (0.303 MPa, 275 K) = 28.7 kJ/kg K
H
h2 (4.04 MPa, 300 K) = 1586 kJ/kg
$2 (4.04 MPa, 300 K) = 23.75 kJ/kg K
h3 (4.04 MPa, 190 K) = 1013 kJ/kg
$3 (4.04 MPa, 190 K) = 21.4 kJ/kg K
h7(0.101 MPa, saturated vapor) = 31 kJjkg
$7(0.101 MPa, saturated vapor) = 8.4 kJjkg K
hf (0.101 MPa, saturated liquid) = 10 kJjkg
sf (0.101 MPa, saturated liquid) = 3.45 kJjkg K
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www
Transcribed Image Text:Helium gas is compressed from 0.303 MPa and 275 K to 4.04 MPa and 300 K in a Claude refrigerator utilizing a wet expander with a saturated-vapor compressor. Twenty percent of the compressed gas is diverted through the main expander entering at 190 K and leaving at 0.303 MPa. The helium enters the low temperature compressor at 0.101 MPa as saturated vapor and leaves at 0.303 MPa. If the compressors, expanders and heat exchangers for this refrigerator are assumed to be ideal, determine the refrigeration effect, coefficient of performance and figure of merit when no expander work is recovered. The following thermodynamic properties are obtained from the temperature--entropy diagram for helium: hl (0.303 MPa, 275 K) = 1444 kJj/kg s1 (0.303 MPa, 275 K) = 28.7 kJ/kg K H h2 (4.04 MPa, 300 K) = 1586 kJ/kg $2 (4.04 MPa, 300 K) = 23.75 kJ/kg K h3 (4.04 MPa, 190 K) = 1013 kJ/kg $3 (4.04 MPa, 190 K) = 21.4 kJ/kg K h7(0.101 MPa, saturated vapor) = 31 kJjkg $7(0.101 MPa, saturated vapor) = 8.4 kJjkg K hf (0.101 MPa, saturated liquid) = 10 kJjkg sf (0.101 MPa, saturated liquid) = 3.45 kJjkg K ww www
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