Heat of Formation Use a standard enthalpies of formation table to determine the change in enthalpy for each of these reactions. a) NaOH(s) + HCl(g) → NaCl(s) + H₂O(g) b) 2 CO(g)+O2(g) > 2 CO2(g) c) CH4(g) +2 O02(g) → CO2(g) + 2 H₂O(1) d) 2 H₂S(g) + 3 O2(g) → 2 H₂O(1) +2 SO₂(g) e) 2 NO(g) + O2(g) → 2 NO2(g) Compound CH4(g) CO₂(g) NaCl(s) H₂O(1) H₂S(g) H₂SO4(1) MgSO4(s) MnO(s) MnO₂(s) NaCl(s) NaF(s) NaOH(s) NH3(g) CO (g) AH (kJ/mol) -74.8 -393.5 -411.0 -285.8 -20.1 -811.3 -1278.2 -384.9 -519.7 -411.0 -569.0 -426.7 -46.2 -110.5 Compound HCI(g) H₂O(g) SO₂(g) NH4Cl(s) NO(g) NO₂(g) SnCl4(1) SnO(s) SnO₂(s) SO₂(g) SO3(g) ZnO(s) ZnS(s) AH (kJ/mol) -92.3 -241.8 -296.1 -315.4 +90.4 +33.9 -545.2 -286.2 -580.7 -296.1 -395.2 -348.0 -202.9

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Please answer super fast and super important please answer part d and c Provide all steps please
**Heat of Formation**

Use a standard enthalpies of formation table to determine the change in enthalpy for each of these reactions.

a) \(\text{NaOH(s)} + \text{HCl(g)} \rightarrow \text{NaCl(s)} + \text{H}_2\text{O(g)}\)

b) \(2 \text{CO(g)} + \text{O}_2\text{(g)} \rightarrow 2 \text{CO}_2\text{(g)}\)

c) \(\text{CH}_4\text{(g)} + 2 \text{O}_2\text{(g)} \rightarrow \text{CO}_2\text{(g)} + 2 \text{H}_2\text{O(l)}\)

d) \(2 \text{H}_2\text{S(g)} + 3 \text{O}_2\text{(g)} \rightarrow 2 \text{H}_2\text{O(l)} + 2 \text{SO}_2\text{(g)}\)

e) \(2 \text{NO(g)} + \text{O}_2\text{(g)} \rightarrow 2 \text{NO}_2\text{(g)}\)

**Standard Enthalpies of Formation (\( \Delta H_f \))**

| Compound    | \( \Delta H_f \) (kJ/mol) | Compound    | \( \Delta H_f \) (kJ/mol) |
|-------------|----------------------------|-------------|----------------------------|
| CH\(_4\)(g) | -74.8                      | HCl(g)      | -92.3                      |
| CO\(_2\)(g) | -393.5                     | H\(_2\)O(g) | -241.8                     |
| NaCl(s)     | -411.0                     | SO\(_2\)(g) | -296.1                     |
| H\(_2\)O(l) | -285.8                     | NH\(_4\)Cl(s) | -315.4                     |
| H\(_2\)S(g) | -20.1                      | NO(g)       | +90.4                      |
| H\(_2\)SO\(_4\)(l
Transcribed Image Text:**Heat of Formation** Use a standard enthalpies of formation table to determine the change in enthalpy for each of these reactions. a) \(\text{NaOH(s)} + \text{HCl(g)} \rightarrow \text{NaCl(s)} + \text{H}_2\text{O(g)}\) b) \(2 \text{CO(g)} + \text{O}_2\text{(g)} \rightarrow 2 \text{CO}_2\text{(g)}\) c) \(\text{CH}_4\text{(g)} + 2 \text{O}_2\text{(g)} \rightarrow \text{CO}_2\text{(g)} + 2 \text{H}_2\text{O(l)}\) d) \(2 \text{H}_2\text{S(g)} + 3 \text{O}_2\text{(g)} \rightarrow 2 \text{H}_2\text{O(l)} + 2 \text{SO}_2\text{(g)}\) e) \(2 \text{NO(g)} + \text{O}_2\text{(g)} \rightarrow 2 \text{NO}_2\text{(g)}\) **Standard Enthalpies of Formation (\( \Delta H_f \))** | Compound | \( \Delta H_f \) (kJ/mol) | Compound | \( \Delta H_f \) (kJ/mol) | |-------------|----------------------------|-------------|----------------------------| | CH\(_4\)(g) | -74.8 | HCl(g) | -92.3 | | CO\(_2\)(g) | -393.5 | H\(_2\)O(g) | -241.8 | | NaCl(s) | -411.0 | SO\(_2\)(g) | -296.1 | | H\(_2\)O(l) | -285.8 | NH\(_4\)Cl(s) | -315.4 | | H\(_2\)S(g) | -20.1 | NO(g) | +90.4 | | H\(_2\)SO\(_4\)(l
Expert Solution
Step 1: Introduction to the change in standard enthalpy of the reaction

The change in standard enthalpy of the reaction is given by

capital delta H degree subscript r x n end subscript equals sum n subscript p cross times capital delta H degree subscript f left parenthesis p r o d u c t s right parenthesis minus sum n subscript r cross times capital delta H degree subscript f left parenthesis r e a c tan t s right parenthesis

np = represents the stoichiometric coefficients of the products,

nr = represents the stoichiometric coefficients of thereactants

capital delta H degree subscript f = represents the standard enthalpies of formation

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