heart defibrillator being used on a patient has an RC time constant of 11 ms due to the resistance of the patient's body and the capacitance of the defibrillator. t = 11 ms C = 8.5 uF V = 14 kV (b) If the initial voltage is 14 kV, how long does it take to decline to 6.00 x 10^2 V in ms?

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A heart defibrillator being used on a patient has an RC time constant of 11 ms due to the resistance of the patient's body and the capacitance of the defibrillator.

t = 11 ms

C = 8.5 uF

V = 14 kV

(b) If the initial voltage is 14 kV, how long does it take to decline to 6.00 x 10^2 V in ms?

 

(11%) Problem 9: A heart defibrillator being used on a patient has an RC time constant of 11 ms due to the resistance of the patient's body and the
capacitance of the defibrillator.
Randomized Variables
T = 11 ms
C = 8.5 µF
V =14 kV
50% Part (a) If the defibrillator has an 8.5 uF capacitance, what is the resistance of the path through the patient in k2? (You may neglect the capac
of the patient's body and the resistance of the defibrillator.)
R= 1.294
V Correct!
* 50% Part (b) If the initial voltage is 14 kV, how long does it take to decline to 6.00 x 102 V in ms?
Grade Summary
Deductions
Potential
t = 471
Submissions
tan()
7
8.
6.
НОME
sin()
cos()
Attempts remainin
(0%, per attempt)
detailed view
cotan()
asin()
acos()
E 1^
4
atan()
acotan()
sinh()
*
1
1
cotanh()
0.
cosh()
tanh()
END
O Degrees
Radians
VO BACKSPACE
CLEAR
3
DEL
Submit
Hint
Feedback
I give up!
Hints: 0% deduction per hint. Hints remaining: 1
Feedback: 0% deduction per feedback.
All content 2022 Expert TA, LLC
3.
2.
Transcribed Image Text:(11%) Problem 9: A heart defibrillator being used on a patient has an RC time constant of 11 ms due to the resistance of the patient's body and the capacitance of the defibrillator. Randomized Variables T = 11 ms C = 8.5 µF V =14 kV 50% Part (a) If the defibrillator has an 8.5 uF capacitance, what is the resistance of the path through the patient in k2? (You may neglect the capac of the patient's body and the resistance of the defibrillator.) R= 1.294 V Correct! * 50% Part (b) If the initial voltage is 14 kV, how long does it take to decline to 6.00 x 102 V in ms? Grade Summary Deductions Potential t = 471 Submissions tan() 7 8. 6. НОME sin() cos() Attempts remainin (0%, per attempt) detailed view cotan() asin() acos() E 1^ 4 atan() acotan() sinh() * 1 1 cotanh() 0. cosh() tanh() END O Degrees Radians VO BACKSPACE CLEAR 3 DEL Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. All content 2022 Expert TA, LLC 3. 2.
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