Q10: 5 ml bleach solution is diluted to exactly 100 ml. A 35 ml of the diluted solution is titrated with 10 ml of 0.30 M Na₂S₂O3 to reach the endpoint, What is the percent by mass of chlorine Cl₂ in the original bleach.( dbleach 1.08 g/ml, M.mass Cl₂-71 g/mol) Hint: 1₂ +2C1 Cl₂ + 21 and 2S₂03² + 12 B) 6.57% C) 5.63% A) 3.94% →21+S406² D) 4.9% E) 7.89% Q11: The following data were obtained for the reaction: S₂02 +212SO4 + 12, and the rate law is: rate= K[S₂08][I]". Determine the values of reaction orders, m, and n. Trial 1 2 3 = 0.20 M Nal (mL) 2 2 4 0.20 M NaCl (mL) 2 2 0 0.0050 M Na₂S₂O3 (mL) 1 1 1 2% starch (mL) 1 1 1 0.10 M K₂SO4 (mL) 2 0 2 Q14: What is the PH of a solution if the [H'] is 4.7×10 ³M? A) 6.7 B) 7.3 C) 2.3 0.10 M K₂S208 (mL) 2 4 2 D) 3 Q13: Calculate the molar solubility of Ca(OH)2 in a 0.012 M CaCl₂ solution. Ksp 6.5×10% A)23 ×103 B) 9x10³ C) 11.6×10-³ D) 4.5×103 E) 5.4×104 A) n=1, m=2 B) n=2, m=1 C) n=1, m=1 D) n=2, m=2 Q12: The solubility product Ksp expression for Ca3(PO4)2 is: A) [Ca][PO] B) [Ca][PO] C) [Ca][PO] D) [Ca][PO] E) [Ca]³[PO4³1² E) None of them Reaction time(At) (sec) 70 36 35 E) 4.7 69 34 36
Q10: 5 ml bleach solution is diluted to exactly 100 ml. A 35 ml of the diluted solution is titrated with 10 ml of 0.30 M Na₂S₂O3 to reach the endpoint, What is the percent by mass of chlorine Cl₂ in the original bleach.( dbleach 1.08 g/ml, M.mass Cl₂-71 g/mol) Hint: 1₂ +2C1 Cl₂ + 21 and 2S₂03² + 12 B) 6.57% C) 5.63% A) 3.94% →21+S406² D) 4.9% E) 7.89% Q11: The following data were obtained for the reaction: S₂02 +212SO4 + 12, and the rate law is: rate= K[S₂08][I]". Determine the values of reaction orders, m, and n. Trial 1 2 3 = 0.20 M Nal (mL) 2 2 4 0.20 M NaCl (mL) 2 2 0 0.0050 M Na₂S₂O3 (mL) 1 1 1 2% starch (mL) 1 1 1 0.10 M K₂SO4 (mL) 2 0 2 Q14: What is the PH of a solution if the [H'] is 4.7×10 ³M? A) 6.7 B) 7.3 C) 2.3 0.10 M K₂S208 (mL) 2 4 2 D) 3 Q13: Calculate the molar solubility of Ca(OH)2 in a 0.012 M CaCl₂ solution. Ksp 6.5×10% A)23 ×103 B) 9x10³ C) 11.6×10-³ D) 4.5×103 E) 5.4×104 A) n=1, m=2 B) n=2, m=1 C) n=1, m=1 D) n=2, m=2 Q12: The solubility product Ksp expression for Ca3(PO4)2 is: A) [Ca][PO] B) [Ca][PO] C) [Ca][PO] D) [Ca][PO] E) [Ca]³[PO4³1² E) None of them Reaction time(At) (sec) 70 36 35 E) 4.7 69 34 36
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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pleeeeeeease solve question 14
![Q10: 5 ml bleach solution is diluted to exactly 100 ml. A 35 ml of the diluted solution is titrated with 10
ml of 0.30 M Na₂S₂O3 to reach the endpoint, What is the percent by mass of chlorine Cl₂ in the original
bleach.( dbleach 1.08 g/ml, M.mass Cl₂-71 g/mol)
Hint: 1₂ +2C1
Cl₂ + 21 and 2S₂03² + 12
B) 6.57%
C) 5.63%
A) 3.94%
→21+S406²
D) 4.9%
E) 7.89%
Q11: The following data were obtained for the reaction: S₂02 +212SO4 + 12, and the rate law is:
rate= K[S₂08][I]". Determine the values of reaction orders, m, and n.
Trial
1
2
3
=
0.20 M
Nal
(mL)
2
2
4
0.20 M
NaCl
(mL)
2
2
0
0.0050 M
Na₂S₂O3
(mL)
1
1
1
2%
starch
(mL)
1
1
1
0.10 M
K₂SO4
(mL)
2
0
2
Q14: What is the PH of a solution if the [H'] is 4.7×10 ³M?
A) 6.7
B) 7.3
C) 2.3
0.10 M
K₂S208
(mL)
2
4
2
D) 3
Q13: Calculate the molar solubility of Ca(OH)2 in a 0.012 M CaCl₂ solution. Ksp 6.5×10%
A)23 ×103 B) 9x10³
C) 11.6×10-³
D) 4.5×103
E) 5.4×104
A) n=1, m=2
B) n=2, m=1
C) n=1, m=1
D) n=2, m=2
Q12: The solubility product Ksp expression for Ca3(PO4)2 is:
A) [Ca][PO] B) [Ca][PO] C) [Ca][PO] D) [Ca][PO] E) [Ca]³[PO4³1²
E) None of them
Reaction
time(At)
(sec)
70
36
35
E) 4.7
69
34
36](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5ba93354-1db0-4f3a-baeb-3d2f323fa973%2F2dd4cf38-88a1-4e14-9e73-12ac34c37678%2Fx7ids1_processed.png&w=3840&q=75)
Transcribed Image Text:Q10: 5 ml bleach solution is diluted to exactly 100 ml. A 35 ml of the diluted solution is titrated with 10
ml of 0.30 M Na₂S₂O3 to reach the endpoint, What is the percent by mass of chlorine Cl₂ in the original
bleach.( dbleach 1.08 g/ml, M.mass Cl₂-71 g/mol)
Hint: 1₂ +2C1
Cl₂ + 21 and 2S₂03² + 12
B) 6.57%
C) 5.63%
A) 3.94%
→21+S406²
D) 4.9%
E) 7.89%
Q11: The following data were obtained for the reaction: S₂02 +212SO4 + 12, and the rate law is:
rate= K[S₂08][I]". Determine the values of reaction orders, m, and n.
Trial
1
2
3
=
0.20 M
Nal
(mL)
2
2
4
0.20 M
NaCl
(mL)
2
2
0
0.0050 M
Na₂S₂O3
(mL)
1
1
1
2%
starch
(mL)
1
1
1
0.10 M
K₂SO4
(mL)
2
0
2
Q14: What is the PH of a solution if the [H'] is 4.7×10 ³M?
A) 6.7
B) 7.3
C) 2.3
0.10 M
K₂S208
(mL)
2
4
2
D) 3
Q13: Calculate the molar solubility of Ca(OH)2 in a 0.012 M CaCl₂ solution. Ksp 6.5×10%
A)23 ×103 B) 9x10³
C) 11.6×10-³
D) 4.5×103
E) 5.4×104
A) n=1, m=2
B) n=2, m=1
C) n=1, m=1
D) n=2, m=2
Q12: The solubility product Ksp expression for Ca3(PO4)2 is:
A) [Ca][PO] B) [Ca][PO] C) [Ca][PO] D) [Ca][PO] E) [Ca]³[PO4³1²
E) None of them
Reaction
time(At)
(sec)
70
36
35
E) 4.7
69
34
36
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