he vector v = , is tangent to the surface x2 + 2y3 - 3z2 = 3 at the point (2, 1, 1).  Find a.

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The vector v = <a, 1, -1>, is tangent to the surface x2 + 2y3 - 3z2 = 3 at the point (2, 1, 1). 

Find a. 

Expert Solution
Step 1: Tangent bector to the surface

G i v e n space s u r f a c e space i s space
x squared plus 2 y squared minus 3 z squared equals 3
f left parenthesis x comma y comma z right parenthesis equals x squared plus 2 y squared minus 3 z squared minus 3 equals 0

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