he two tangents AV and VB are connected by a compound curve at points A (P.C.) and B (P.T.). Point V is the point of intersection (P.I.). Angle VAB = 40° and angle VBA = 30°. The radius of the first curve is 175m and the distance between AB is 350m. a) Compute for the central angle of the first curve. b) Compute for the central angle of the second curve. c) Compute for the radi

A compound curve connects three tangents having an azimuths of 250°, 270 ° and 290° respectively. The length of the chord is 340m long measured from the P.C to the P.T of the curve and is parallel to the common tangent having an azimuth 270 °. If the stationing of P.T is 6+000 a) Plot the compound curve b) Compute all of the elements of a compound Curve. c) Determine the stationing by the interval of 20 of the curve

QUESTION 2 Two tangents AB and BC intersect at an angle of 24°0'0". A curve is formed from point A to C. A point on the curve, D, is found along the curve near A. Point D is located 21.03 m from point B, and has a perpendicular distance of 2.79 m from line AB. a. Calculate the radius of the simple curve connecting the two tangents and passing point D Answer: R= m b. Calculate the length of the chord connecting PC and point D Answer: C = m Note: Unit has been provided after the blank space. No need to indicate units on your answer. Use sexagesimal units for angle measurements.

2. The tangent lines of a simple curve have azimuths 300° and bearing N 04 E, respectively. A third tangent line AB intersects the two tangent lines at bearing S 34° E. Stationing of the PI of the curve is 16 + 464.35 and the distance from point B to the PI of the curve is 277.6 m (ie BV = 277.6 m). Determine the following: a. Radius of the simple curve that shall be tangent to these three lines. b. Stationing of the PC c. Stationing of the PT

A simple curve connects two tangents AB and BC bearings N 85°30' E and S 68°30' E respectively. Point D along line AB has a coordinate of 20100 N and 20100 E while point E along line BC has coordinates of 20086.55 N and 20184.27 E 1. Find the distance of line BD. 2. Solve for the degree of simple curve that shall be tangent to the three AB, DE and BC 3. If point D at station 1 + 052.87 determine the stationing of PT.

The offset distance of the simple curve from PT to the tangent line passing through the PC is equal to 120.20m. The stationing of PC is at 2 + 540.26. The simple curve has an angle of intersection of 500. a. Compute the degree of curve.b. Compute the external distance.c. Compute the length of the long chord.

The perpendicular distance between the two parallel tangents is 8 meters. The central angles are equal to 15° and the radius of curvature of the first curve is equal to 185 meters. a. Find the radius of the second curve. b.  Find the length of the long chord from point of curvature to point of tangency. c. Find the stationing at point of tangency and at point of reversed curvature if the station at point of curvature is 10 + 350.

Two tangent of a simple curve have azimuths of 248°15' and 294°30' are connected by a 4.2° curve. If sta. V is at 7 + 196.25, compute the other elements of the curve. a. The radius of the curve. b. The external distance of the curve. C. The middle ordinate of the curve.

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1. In a compound curve, the line connecting the PI at point V and the PCC is an angle bisector. AV is 270 90 LB (6+721) (6+421) A 270 meters and BV=90 m. The P.T. stationing of A is 6+421 and that of B is 6+721. Point A is along the tangent passing through the PC while point B is along the tangent P.C passing through the PT. The PCC is along line AB. Compute for the length of the radii for both curves.