Please label each part O Part (j)Using the least squares line, find the estimated life expectancy for an individual born in 1810. (Round your answer to one decimal place.)Does the least squares line give an accurate estimate for that year? Explain why or why not.Yes, because the estimate is over 50 years.No, because 1810 is outside the domain of the least squares line.Part (k)What is the slope of the least-squares (best-fit) line? (Round your answer to three decimal places.)Interpret the slope. (Round your answer to three decimal places.)As theyear of birthincreases by one year, thelife expectancy Oincreases byyears. The table below shows the life expectancy for an individual born in the United States in certain years.Year of BirthLife Expectancy193059.7194062.9195070.2196569.7197371.4198274.5198775199275.7201078.7+ Part (a)Part (b)E Part (c)Calculate the least squares line. Put the equation in the form of ý = a + bx. (Round your answers to three decimal places.)シ=+Part (d)Find the correlation coefficient r. (Round your answer to four decimal places.)r =Is it significant?YesNoPart (e)Find the estimated life expectancy for an individual born in 1930 and for one born in 2010. (Round your answers to one decimal place.)Birthdate in 1930:Birthdate in 2010:

Given Information: The life expectancy for an individual born in the united states in certain years. For the given data, (c) Regression equation can be obtained using Excel, step-by-step procedure is given below: Enter the data in Excel sheet Go to DATA -> Data Analysis, select Regression Enter Input Y range (Life expectancy) and X range (Year of Birth) Check on labels, select Output range Click ok. Excel output is given below: From the output, Intercept is -377.243 and slope is 0.227 Thus, the regression equation is : y^=a+bx=-377.243+0.227x(d) Using Excel function "=CORREL(X range, Y range)" i.e., "=CORREL(A1:A10,B1:B10)", correlation coefficient r is 0.961261 ≈0.9613 (e) To find the estimated life expectancy for an individual born in 1930: y^=-377.243+0.227x=-377.243+0.227×1930=60.867≈60.9 Estimated life expectancy for an individual born in 2010: y^=-377.243+0.227x=-377.243+0.227×2010=79.027≈79.0 Since, there are multiple subparts, we have solved three subparts for you. To get remaining subparts solved, please repost the complete question and mention the subparts to be solved.