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he scher below long simply supported beam (resting exterior inge on the left, and a roller on the right). This beam is subject to a combination of oncentrated moment (750 kN-m at section C), concentrated force (300 kN at section D), nd distributed load (15 kN/m between sections E and B). 300 kN 15 kN/m 750 kN-m F 5 m5 m 5 m 5m 5 m 25 m Determine the reaction forces at the supports in A and B, and indicate the directions in which these forces act. Note: this question counts for the pass/no-pass

he scher below long simply supported beam (resting exterior inge on the left, and a roller on the right). This beam is subject to a combination of oncentrated moment (750 kN-m at section C), concentrated force (300 kN at section D), nd distributed load (15 kN/m between sections E and B). 300 kN 15 kN/m 750 kN-m F 5 m5 m 5 m 5m 5 m 25 m Determine the reaction forces at the supports in A and B, and indicate the directions in which these forces act. Note: this question counts for the pass/no-pass

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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**Educational Website Text:** ### Statics Problem - Beam Analysis **Diagram Explanation:** The schematic illustrates a simply supported beam with a total length of 25 meters. The beam rests on a hinge at the left support (point A) and a roller at the right support (point B). It is subjected to the following loads and moments: - A concentrated moment of 750 kN·m at section C. - A concentrated force of 300 kN at section D. - A distributed load of 15 kN/m applied over sections E to B. **Section Lengths:** - AC = 5 m - CD = 5 m - DE = 5 m - EB = 10 m **Problem Statement:** 1. **Reaction Forces:** - Determine the reaction forces at supports A and B. - Indicate the directions in which these forces act. - Note: This question serves as a pass/no-pass "minimum-proficiency test" for Statics. 2. **Shear Function V(x):** - Determine the shear function \( V(x) \) along the x domains: - AC (0 ≤ x ≤ 5 m) - CD (5 m ≤ x ≤ 10 m) - DE (10 m ≤ x ≤ 15 m) - EB (15 m ≤ x ≤ 25 m) - Draw the shear diagram for the entire beam. - Note: Use the reference axis x as indicated in the diagram. 3. **Moment Function M(x):** - Determine the moment function \( M(x) \) along each x domain across the entire beam. - Draw the moment diagram for the entire beam. **Points:** - Reaction Forces: 20 points - Shear Function: 20 points - Moment Function: 20 points **Notes:** - Follow the reference x-axis as shown in the diagram. - The uniform distributed load begins at section E and continues to section B. This structured approach aims to enhance understanding of how forces and moments distribute along a beam, essential for aspiring civil or structural engineers.
Transcribed Image Text:**Educational Website Text:** ### Statics Problem - Beam Analysis **Diagram Explanation:** The schematic illustrates a simply supported beam with a total length of 25 meters. The beam rests on a hinge at the left support (point A) and a roller at the right support (point B). It is subjected to the following loads and moments: - A concentrated moment of 750 kN·m at section C. - A concentrated force of 300 kN at section D. - A distributed load of 15 kN/m applied over sections E to B. **Section Lengths:** - AC = 5 m - CD = 5 m - DE = 5 m - EB = 10 m **Problem Statement:** 1. **Reaction Forces:** - Determine the reaction forces at supports A and B. - Indicate the directions in which these forces act. - Note: This question serves as a pass/no-pass "minimum-proficiency test" for Statics. 2. **Shear Function V(x):** - Determine the shear function \( V(x) \) along the x domains: - AC (0 ≤ x ≤ 5 m) - CD (5 m ≤ x ≤ 10 m) - DE (10 m ≤ x ≤ 15 m) - EB (15 m ≤ x ≤ 25 m) - Draw the shear diagram for the entire beam. - Note: Use the reference axis x as indicated in the diagram. 3. **Moment Function M(x):** - Determine the moment function \( M(x) \) along each x domain across the entire beam. - Draw the moment diagram for the entire beam. **Points:** - Reaction Forces: 20 points - Shear Function: 20 points - Moment Function: 20 points **Notes:** - Follow the reference x-axis as shown in the diagram. - The uniform distributed load begins at section E and continues to section B. This structured approach aims to enhance understanding of how forces and moments distribute along a beam, essential for aspiring civil or structural engineers.
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