he pmf of a discrete random variable X is as follows: X -1 0 1 2 f(x) 1/10 2/10 5/10 2/10 Use this pmf to evaluate the following: mean of X variance of X
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- The pmf of a discrete random variable X is as follows:
|
X |
-1 |
0 |
1 |
2 |
|
f(x) |
1/10 |
2/10 |
5/10 |
2/10 |
Use this pmf to evaluate the following:
mean of X- variance of X
Step by step
Solved in 3 steps
- Which of the following statements about dependent samples t-test is false? - Dependent samples t-test must be non-directional tests - The formulas for dependent samples measures are similar to formulas used for X, s, s, _e - The hypothesis testing procedure follows the familiar process - Equal variances are assuredModule 5: Ihd Use the table of values and the expected frequencies to calculate the residual values and the chi square test statistic X XYZ A 34 44 22 B 19 53 32 Expected Frequencies A 25.98 47.549 26.471 B 27.02 49.451 27.529 Residual Values (Row i and column j) Chi Square Test Statistic (0.,, – E. ) E (0 – E) x =E E Round all values to 3 decimal places Y B The Chi Square Test Statistic x =If G is used to estimate γ and the expected value of G is γ , what can be said about G? Group of answer choices G has minimum variance. G is biased as an estimator of γ G is not a point estimator of γ G is unbiased as an estimator of γ G is a M.V.U.E of γ None of these
- Batting Averages Random samples of batting averages from the leaders in both leagues prior to the All-Star break are shown. At the 0.10 level of significance, can a difference be concluded? Use the P-value method and a TI-83 Plus/TI-84 Plus calculator. Assume the variables are normally distributed and the variances are unequal. Use , for the National League average. National 0.315 0.320 0.317 0.349 0.319 0.322 American 0.336 0.345 0.352 0.348 0.328 0.323 Send data to Excel Part: 0/4 Part 1 of 4 State the hypotheses and identify the claim with the correct hypothesis. Ho: (Choose one) H₁ : (Choose one) This hypothesis test is a (Choose one) test.Which statement is false? Levine's test for the quality of variance is used with the dependent t-test The dependent t-test is considered more powerful than the independent t-test Parametric tests are considered more powerful than non-parametric You can typically use a small sample with the dependent t-test compared to the independent t-testeconometrics question. Please prove
- Test Scores An instructor who taught an online statistics course and a classroom course feels that the variance of the final exam scores for the students who took the online course is greater than the variance of the final exam scores of the students who took the classroom final exam. The following data were obtained. At =α0.05 is there enough evidence to support the claim? Use σ21 for the variance of the online scores. Use the critical value method and tables. State the Hypothesis and Identify the claim: H0: Claim or not a claim H1: Claim or not a claim Find the critical Value: Round the answer to at least two decimal places. Compute the test value: Make the decision reject or accept the null hypothesis. Summarize the results. Is there enough evidence to support the claim? Online Course Classroom Course =s13.4 =s22.2 =n121 =n231ont Paragraph Styles Editing -A professor from a Quantitative Methods in Business course decided to research the relationship between the Mid Term Exam, the average number of study hours spent per week during the semester and the final course grade for a given student. A sample of containing data from a previous semester was provided by the instructor and summarized in the following table: # of Students Mid-Term exam Study hours per Final course grade week grade 1 50.0 2.0 65.0 60.0 4.0 85.0 55.0 3.5 75.0 4 85.0 6.0 90.0 55.0 5.0 70.0 6. 72.0 4.5 89.0 7 75.0 6.5 91.0 8 45.0 3.0 65.0 6. 88.0 5.5 89.0 10 90.0 7.5 96.0 Develop a linear regression model, where Y is the Final Grade Course and X is the Mid-Term Exam. Calculate the coefficient of determination (r 2 , the coefficient of correlation (r), the variance (o 2) for Text Predictions: OnTreatment Sham Researchers conducted a study to determine whether magnets are effective in treating back pain. The results are shown in the table for the treatment (with magnets) group and the sham (or placebo) group. The results are a measure u of reduction in back pain. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. H1 H2 In 10 10 0.56 0.37 0.97 1.45 O B. Ho: H1 + H2 O A. Ho: H1 = H2 H1: H1 # H2 H1: H1 H2 H1: H12 H2 The test statistic, t, is|. (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) State the conclusion for the test. V the null hypothesis. There V sufficient evidence to support the claim that those treated with magnets have a greater mean reduction in pain than those given a sham treatment. Is it valid to argue that magnets might appear to be effective if the…
- Which of the following are true? (Select all that apply.) 1 An assumption of a linear regression is a consistent dispersion of the observations from the regression line. 2 An assumption of a linear regression is that the residuals form a normal distribution. 3 Omitted variable bias is when you don’t include the dependent variable.BUS – 173 (Applied Statistics) # Determining if the following statement are True and False. If False, write the correct statement. 01. The value of the perfect positive correlation is -1 (a) True (b) False 02. In the Simple linear regression model, components of the random error term are assumed to be dependent (a) True (b) False 03. In the Simple linear regression model, components of the random error term have fixed mean zero. (a) True (b) False
