he other part of the question is: If the null hypothesis is rejected, what is the actual risk of having made a wrong decision? Enter the answer in percent and round it to the nearest integer. For example if the probability of wrong decision is 0.155, multiply it by 100 to change it to percent (100*0.155=15.5), and then round it to the nearest integer which would be 16.  Enter 16 in the answer text box.  If there is not enough information available to compute the probability enter “N” in the answer text box The answer is (percent in integer format/N): Which of the followings is/are appropriate conclusion for the hypotheses test?  Note that there may be more than one appropriate conclusion. Enter “A” if the conclusion is appropriate and enter “N” if the conclusion is not appropriate. At 90% confidence level, the data supports that the afternoon bus ridership is higher than the morning. The answer(A/N) is: At 90% confidence level, the data does not support that the afternoon bus ridership is higher than the morning. The answer (A/N) is: With a maximum risk of 5% of being wrong, we can conclude that the data supports that the afternoon bus ridership is higher than the morning. The answer (A/N) is:

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The other part of the question is: If the null hypothesis is rejected, what is the actual risk of having made a wrong decision? Enter the answer in percent and round it to the nearest integer. For example if the probability of wrong decision is 0.155, multiply it by 100 to change it to percent (100*0.155=15.5), and then round it to the nearest integer which would be 16.  Enter 16 in the answer text box.  If there is not enough information available to compute the probability enter “N” in the answer text box The answer is (percent in integer format/N): Which of the followings is/are appropriate conclusion for the hypotheses test?  Note that there may be more than one appropriate conclusion. Enter “A” if the conclusion is appropriate and enter “N” if the conclusion is not appropriate. At 90% confidence level, the data supports that the afternoon bus ridership is higher than the morning. The answer(A/N) is: At 90% confidence level, the data does not support that the afternoon bus ridership is higher than the morning. The answer (A/N) is: With a maximum risk of 5% of being wrong, we can conclude that the data supports that the afternoon bus ridership is higher than the morning. The answer (A/N) is:
1. Ho: Hd20
Hạ: Hd <0 the difference is computed as: average number of morning riders – average number of afternoon riders
. Họ: Pm - Pas 0
Ha: Pm - Pa>0
. Ho: Pm - Pa 20 Ha: Pm- Pa <0
Your answer is:
enter the absolute value of your answer in the response text box. Do not include the plus or minus sign with your
answer, Enter the answer in X.XXX format. That is, first round your answer to three decimals ånd then use leading and trailing zeros to exactly
match the format. For example, if your answer is 6.1525, first round it to three decimals which is 6.153 and then enter it as 6.153 to match the
format. If your answer is -0.2 then enter it as 0.200 in the answer box and do not include the minus sign. If your answer is 0.32 then enter it as
0.320 to match the format.
What is the value of the test statistics? Enter the answer in x.xxx format per instructions for part b.
Your answer is:
What is the P-value? Enter the answer in X.XXx format per instructions for part b.
Your answer is:
I What is your decision?
Enter "R" if your decision is to reject the null hypotheses. Enter "F" if the decision is do not reject the null hypotheses.
Your answer (R/F) is:
dagigion?
Transcribed Image Text:1. Ho: Hd20 Hạ: Hd <0 the difference is computed as: average number of morning riders – average number of afternoon riders . Họ: Pm - Pas 0 Ha: Pm - Pa>0 . Ho: Pm - Pa 20 Ha: Pm- Pa <0 Your answer is: enter the absolute value of your answer in the response text box. Do not include the plus or minus sign with your answer, Enter the answer in X.XXX format. That is, first round your answer to three decimals ånd then use leading and trailing zeros to exactly match the format. For example, if your answer is 6.1525, first round it to three decimals which is 6.153 and then enter it as 6.153 to match the format. If your answer is -0.2 then enter it as 0.200 in the answer box and do not include the minus sign. If your answer is 0.32 then enter it as 0.320 to match the format. What is the value of the test statistics? Enter the answer in x.xxx format per instructions for part b. Your answer is: What is the P-value? Enter the answer in X.XXx format per instructions for part b. Your answer is: I What is your decision? Enter "R" if your decision is to reject the null hypotheses. Enter "F" if the decision is do not reject the null hypotheses. Your answer (R/F) is: dagigion?
A study is conducted to determine if bus ridership in a large city is higher during the afternoon rush hours than morning rush hours. The transit
authority randomly selects nine buses and on a given day counts the number of riders at 7:45 AM and 4:45 PM. The results are shown below.
Conduct an appropriate hypothesis test using 0.1 level of significance.
Morning
43
51| 37 25
47
44
48
55
52
Afternoon
41 49
44 32 46 55
53
51
49
Determine which of the following formulations of the hypotheses is most appropriate and enter the corresponding number in the answer text
box.
Note: Index "a" refers to the population of afternoon bus riders and index “m" refers to the population of morning bus riders.
For example if you think formulation number 3 is the most appropriate formulation for this problem then enter "3" in the answer text box and re-enter to
confirm.
Ho: Hm - Ha S0
Ha: Hm - Ha > 0
Họ: Hm - Ha 20
Ha: Hm - Ha < 0
I Ho: Om-Oa s0
Ha: Om -Oa>0
I Ho: Om -Da 20
Ha: Om -0a<0
0 5 Pri :0H
Ha: Hd > 0 the difference is computed as: average number of morning riders - average number of afternoon
riders
I. Ho: Hd20
Ha: Hd <0 the difference is computed as: average number of morning riders - average number of afternoon riders
Transcribed Image Text:A study is conducted to determine if bus ridership in a large city is higher during the afternoon rush hours than morning rush hours. The transit authority randomly selects nine buses and on a given day counts the number of riders at 7:45 AM and 4:45 PM. The results are shown below. Conduct an appropriate hypothesis test using 0.1 level of significance. Morning 43 51| 37 25 47 44 48 55 52 Afternoon 41 49 44 32 46 55 53 51 49 Determine which of the following formulations of the hypotheses is most appropriate and enter the corresponding number in the answer text box. Note: Index "a" refers to the population of afternoon bus riders and index “m" refers to the population of morning bus riders. For example if you think formulation number 3 is the most appropriate formulation for this problem then enter "3" in the answer text box and re-enter to confirm. Ho: Hm - Ha S0 Ha: Hm - Ha > 0 Họ: Hm - Ha 20 Ha: Hm - Ha < 0 I Ho: Om-Oa s0 Ha: Om -Oa>0 I Ho: Om -Da 20 Ha: Om -0a<0 0 5 Pri :0H Ha: Hd > 0 the difference is computed as: average number of morning riders - average number of afternoon riders I. Ho: Hd20 Ha: Hd <0 the difference is computed as: average number of morning riders - average number of afternoon riders
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