The heights of adult females are approximately normally distributed, with an estimated mean of 65.0 inches and an estimated standard deviation of 3.00. Someresearchers hypothesized that the actual standard deviation, o, of heights of adult females is greater than 3.00. These researchers chose a random sample of 20adult females. The mean height of this sample was 64.9 inches, and the standard deviation was 3.44. Is there enough evidence to conclude, at the 0.1 level ofsignificance, that the standard deviation of adult female heights is greater than 3.00?Perform a one-tailed test. Then complete the parts below.Carry your intermediate computations to three or more decimal places and round your answers as specified below. (If necessary, consult a list of formulas.)(a) State the null hypothesis H, and the alternative hypothesis H1.pHo :0H, :0(b) Determine the type of test statistic to use.(Choose one) ▼D=0OSO(c) Find the value of the test statistic. (Round to three or more decimal places.)O

Name: The heights of adult females are approximately normally distributed,
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: The heights of adult females are approximately normally distributed, with an estimated mean of 65.0 inches and an estimated standard deviation of 3.00. Someresearchers hypothesized that the actual standard deviation, o, of heights of adult females i

Solution: Given information: n= 20 Sample size x= 64.9 Sample mean μ= 65.0 Population mean σ=…

Math

Statistics

he heights of adult females are approximately normally distributed, with an estimated mean of 65.0 inches and an estimated standard deviation of 3.00. Som esearchers hypothesized that the actual standard deviation, 6, of heights of adult females is greater than 3.00. These researchers chose a random sample of 2 dult females. The mean height of this sample was 64.9 inches, and the standard deviation was 3.44. Is there enough evidence to conclude, at the 0.1 level of gnificance, that the standard deviation of adult female heights is greater than 3.00? erform a one-tailed test. Then complete the parts below. arry your intermediate computations to three or more decimal places and round your answers as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis Ho and the alternative hypothesis H,- H. :0 H :0 (b) Determine the type of test statistic to use. (Choose one) v O=0 OSO (c) Find the value of the test statistic. (Round to three or more decimal places.) O

he heights of adult females are approximately normally distributed, with an estimated mean of 65.0 inches and an estimated standard deviation of 3.00. Som esearchers hypothesized that the actual standard deviation, 6, of heights of adult females is greater than 3.00. These researchers chose a random sample of 2 dult females. The mean height of this sample was 64.9 inches, and the standard deviation was 3.44. Is there enough evidence to conclude, at the 0.1 level of gnificance, that the standard deviation of adult female heights is greater than 3.00? erform a one-tailed test. Then complete the parts below. arry your intermediate computations to three or more decimal places and round your answers as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis Ho and the alternative hypothesis H,- H. :0 H :0 (b) Determine the type of test statistic to use. (Choose one) v O=0 OSO (c) Find the value of the test statistic. (Round to three or more decimal places.) O

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A research firm supplies manufacturers with estimates of the sales of their products from samples of stores. Marketing managers often look at the sales estimates and ignore sampling error. An SRS of 50 stores this month shows mean sales of 41 units of a particular appliance with standard deviation of 11 units. During the same month last year, an SRS of 52 stores gave mean sales of 38 units of the same appliance with a standard deviation of 13 units. An increase from 38 to 41 is a rise of 7.9%. The marketing manager is happy because sales are up 7.9%. (a) Give a 95% confidence interval for the difference in mean number of units of the appliance sold at all retail stores. Give your answers to three decimal places. lower bound: upper bound:
A firm is looking to employ a person as an engineer. Applicants of earlier years have standart deviation of 35.8. we pick random 75 people who apply to job this year and their mean result of the exam is 167.5. What is the 90 percent confidince interval for the mean of all applicants exam results?
The sample mean weight of 200 adult vulturine parrots was measured to be 734.2 grams, with a standard deviation of 15.7 grams. Using a 10% level of significance, what could we claim about the population mean weight for all vulturine parrots so that the hypothesis will fail to be rejected?
A student at a four-year college claims that mean enrollment at four-year colleges is higher than at two-year colleges in the United States. Two surveys are conducted. Of the 35 four-year colleges surveyed, the mean enrollment was 5,466 with a standard deviation of 8,191. Of the 35 two-year colleges surveyed, the mean enrollment was 5,068 with a standard deviation of 4,777. Test the student's claim at the 0.10 significance level.a) The null and alternative hypothesis would be: �0:��=��1:��>�� 0:��=��1:��≠�� 0:��=��1:��>�� 0:��=��1:��<�� 0:��=��1:��≠�� 0:��=��1:��<�� b) Determine the test statistic. Round to two decimals.�=c) Find the p-value and round to 4 decimals.p =
The heights of adult men in America are normally distributed, with a mean of 69.3 inches and a standard deviation of 2.67 inches. The heights of adult women in America are also normally distributed, but with a mean of 64.8 inches and a standard deviation of 2.54 inches. a) If a man is 6 feet 5 inches tall, what is his z-score? z = 3.26
A student at a four-year college claims that mean enrollment at four-year colleges is higher than at two-year colleges in the United States. Two surveys are conducted. Of the 35 four-year colleges surveyed, the mean enrollment was 5,466 with a standard deviation of 8,191. Of the 35 two-year colleges surveyed, the mean enrollment was 5,068 with a standard deviation of 4,777. Test the student's claim at the 0.10 significance level. a) The null and alternative hypothesis would be: OHO: HF = HT H₁: HF HT O H₁: HF = HT H₁: PF PT t O Ho: PF = PT H₁: PF PT b) Determine the test statistic. Round to two decimals. c) Find the p-value and round to 4 decimals. p= d) Make a decision. O Reject the null hypothesis O Fail to reject the null hypothesis e) Write the conclusion. O There is not sufficient evidence to support the claim that enrollement is high at a four-year college than a two-year college. O There is sufficient evidence to support the claim that enrollement is high at a four-year…
A student at a four-year college claims that mean enrollment at four-year colleges is higher than at two-year colleges in the United States. Two surveys are conducted. Of the 35 four-year colleges surveyed, the mean enrollment was 5,466 with a standard deviation of 8,191. Of the 35 two-year colleges surveyed, the mean enrollment was 5,068 with a standard deviation of 4,777. Test the student's claim at the 0.10 significance level.a) The null and alternative hypothesis would be: �0:��=��1:��>�� 0:��=��1:��≠�� 0:��=��1:��>�� 0:��=��1:��<�� 0:��=��1:��≠�� 0:��=��1:��<�� b) Determine the test statistic. Round to two decimals.�=c) Find the p-value and round to 4 decimals.p =
On a measure of running speed on a 100 meter dash, students received timed scores ranging from 12 seconds to 24 seconds. The distribution of running times is normative with a mean of 16 seconds. Transferring this ratio data to standard scores for comparison with the results of classes from other departments, the mean score is assigned a standard score of 100 with a standard deviation of 10. From this example, a standard score of 99 would mean the actual value in seconds for an individual would be about a. 16 b. 12 c. 19 d. 24
A nurse is interested in the amount of time patients spend exercising per day. According to a recent study, the daily workout time per adult follows an approximately normal distribution with a mean of 94 minutes and a standard deviation of 27minutes. If the nurse randomly samples patients in her office to analyze their exercise time and gets a standard error of 3minutes, how many patients did she sample?