he following data represent t onditions. Treatment Response One 6.8 One 5.4 One 8.5 One 6.8 One 7.5
he following data represent t onditions. Treatment Response One 6.8 One 5.4 One 8.5 One 6.8 One 7.5
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![The following data represent the results from an independent-measures study comparing two treatment conditions.
| Treatment | Response |
|-----------|----------|
| One | 6.8 |
| One | 5.4 |
| One | 8.5 |
| One | 6.8 |
| One | 7.5 |
| One | 5.3 |
| One | 7.1 |
| One | 7.3 |
| Two | 3.6 |
| Two | 2.3 |
| Two | 3.0 |
| Two | 4.2 |
| Two | 1.9 |
| Two | 1.3 |
| Two | 3.2 |
| Two | 4.9 |
| Treatment One | Treatment Two |
|---------------|---------------|
| 6.8 | 3.6 |
| 5.4 | 2.3 |
| 8.5 | 3.0 |
| 6.8 | 4.2 |
| 7.5 | 1.9 |
| 5.3 | 1.3 |
| 7.1 | 3.2 |
| 7.3 | 4.9 |
Conduct ANOVA with \( \alpha = 0.05 \) for this data and calculate the \( F \)-ratio and \( p \)-value. Round your answer to three decimal places. Assume all population and ANOVA requirements are met.
- \( F \)-ratio: 44.78
- \( p \)-value: 0.000
Now, conduct a t-test with \( \alpha = 0.05 \) on the same data and calculate the t-statistic and \( p \)-value. Round your answer to three decimal places.
- t-statistic: 6.690
- \( p \)-value: 0.000
Observing the \( p \)-values, was there a difference in the result of the hypothesis test?
- No, the p-values aren't that far off where it would change the outcome of the test.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5c7e51fb-93c3-4f08-9e0c-24bda278d166%2F1dda3f92-5535-44c6-91f8-7e0b963de4e4%2Fh8vecjb_processed.png&w=3840&q=75)
Transcribed Image Text:The following data represent the results from an independent-measures study comparing two treatment conditions.
| Treatment | Response |
|-----------|----------|
| One | 6.8 |
| One | 5.4 |
| One | 8.5 |
| One | 6.8 |
| One | 7.5 |
| One | 5.3 |
| One | 7.1 |
| One | 7.3 |
| Two | 3.6 |
| Two | 2.3 |
| Two | 3.0 |
| Two | 4.2 |
| Two | 1.9 |
| Two | 1.3 |
| Two | 3.2 |
| Two | 4.9 |
| Treatment One | Treatment Two |
|---------------|---------------|
| 6.8 | 3.6 |
| 5.4 | 2.3 |
| 8.5 | 3.0 |
| 6.8 | 4.2 |
| 7.5 | 1.9 |
| 5.3 | 1.3 |
| 7.1 | 3.2 |
| 7.3 | 4.9 |
Conduct ANOVA with \( \alpha = 0.05 \) for this data and calculate the \( F \)-ratio and \( p \)-value. Round your answer to three decimal places. Assume all population and ANOVA requirements are met.
- \( F \)-ratio: 44.78
- \( p \)-value: 0.000
Now, conduct a t-test with \( \alpha = 0.05 \) on the same data and calculate the t-statistic and \( p \)-value. Round your answer to three decimal places.
- t-statistic: 6.690
- \( p \)-value: 0.000
Observing the \( p \)-values, was there a difference in the result of the hypothesis test?
- No, the p-values aren't that far off where it would change the outcome of the test.
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