he congruences are equivalent in the sense tha solution of one congruence if, and only if, it is a Exercise 1.6 Use an appropriate cancellation to simplify each congruences: (a) 6x18 (mod 30) (b) 20x30 (mod 45) (c) 52x39 (mod 60). D 01:29 PM 39% 01:29 PM ■ 40% a² = 1,25, 49 or 121 (mod 24). But each of these numbers has remainder 1 when divided by 24, and the result follows. Solution to Exercise 1.6 (a) We wish to cancel the common factor 6. As hcf(6,30) = 6, we also divide the modulus by 6: 6x 18 (mod 30) x = 3 (mod 5). (b) In order to cancel the common factor 10, the modulus has to be divided by hcf(10,45) = 5) So 20x = 30 (mod 45) 2x = 3 (mod 9). why? (c) The common factor 13 can be cancelled without adjustment to the modulus, since hcf(13,60) = 1. So 52x39 (mod 60) 4x = 3 (mod 60). 26.92% 76.92%

Q: 01- find the values of x and y for the following:- (1 + i)² 2-i a) = x + yi

A:

Q: Solve for x: 7x = 3 mod 11

A:

Q: Suppose that |u xv = 7. Find ||(5u + 6v) × (3u - 9v)||-

A:

Q: Najabhai

A:

Q: given 7(x-1)=2(3x+2) prove x=11

A:

Q: Please resubmit solution as this instuctions is very uneasy to understand Where did all these…

A: Solution

Q: 3 1 2 8 √x³ 3 2 1 3 X 3 X2 ; 2 - x > ; x ≥ 0x 3 X

A: Given :x31x23x321x-1

Q: 5. Use 1 mile = 5280 feet to solve the problem below. * %3D Two people are looking up at a…

A:

Q: Use your work from problem 2 and the method used in the example at the end of Lecture 16 to solve…

A:

Q: 13 12 dn use ful Ja?_36 Substitution x=6 Seco and rewn'te tue im tegrel

A:

Q: :N N amd 9: N-oN are functions such that f is not onto but f+9 is onto Prove that 9 is onto or give…

A: Suppose that f:ℕ→ℕ and g:ℕ→ℕ are functions such that f is not onto but f+g is onto. To prove that g…