he attached image shows a circuit with an AC voltage source, a resistor, inductor, and capacitor connected in series. The circuit has the following characteristics: Resistor resistance: 10 ohm Capacitor capacitance: 0.05 F Inductor inductance: 13 H Current Amplitude: 4 A Voltage amplitude across the source: 60 V Frequency at the source: 0.3 Hz Voltage amplitude across the resistor: 35 V Voltage amplitude across the capacitor: 37 V  Voltage amplitude across the ind

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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The attached image shows a circuit with an AC voltage source, a resistor, inductor, and capacitor connected in series. The circuit has the following characteristics:

Resistor resistance: 10 ohm

Capacitor capacitance: 0.05 F

Inductor inductance: 13 H

Current Amplitude: 4 A

Voltage amplitude across the source: 60 V

Frequency at the source: 0.3 Hz

Voltage amplitude across the resistor: 35 V

Voltage amplitude across the capacitor: 37 V 

Voltage amplitude across the inductor: 80 V 

(a) Calculate the RMS voltages from the amplitudes above. From the RMS voltages across the capacitor, inductor and resistor, calculate the RMS voltage of the AC source.

Hint: Vrms = V0/sqrt(2)

Vrms = sqrt( (Vrms,R)2 + (Vrms, L - Vrms, C)2 )

(b) Calculate the RMS value of the current

(c) Using the resistance, capacitance, inductance, and the frequency of the AC voltage, calculate the impedance Z. From this, and the previously measured value of Vrms, find the RMS value of the current in the circuit.

 

-43.7 V
Time
Time
10 0
13 H
0.05 F
Current (A)
Transcribed Image Text:-43.7 V Time Time 10 0 13 H 0.05 F Current (A)
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