The accompanying data represent the total travel tax (in dollars) for a 3-day business trip in 8 randomly selected cities. A normal probability plot suggests the data could comefrom a population that is normally distributed. A boxplot indicates there are no outliers. Complete parts (a) through (c) below.68.48 79.88 69.17 84.87 80:59 87:41 100:62 99.59Click the icon to view the table of critical t-values.(Round to two decimal places as needed.)(b) Construct and interpret a 95% confidence interval for the mean tax paid for a three-day business trip.Select the correct choice below and fill in the answer boxes to complete your choice.(Round to two decimal places as needed.).OA. One can beOB. The travel tax is between $OC. One can beD. There is a% confident that the mean travel tax for all cities is between Sand Sand $ for % of all cities.% confident that the all cities have a travel tax between $% probability that the mean travel tax for all cities is betweenand Sand S

Given that data 68.48, 69.17, 79.88, 80.59, 84.87, 87.41, 99.59, 100.62 Sample size n =8

Answered: he accompanying data represent the…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…
Calculate the z-score representing the bottom 10% of an approximately normal distribution. (Use a table or technology. Round your answer to two decimal places.)
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The number of dollars a round trip plane ticket costs from North America to Europe is normally distributed with a mean of $1,780 and a standard deviation of $335. What is the probability a randomly selected ticket costs between $775 and $2,785? Enter your answer in decimal form. For example. 75% should be entered as 0.75
On average, a banana will last 6.5 days from the time it is purchased in the store to the time it is too rotten to eat. Is the mean time to spoil different if the banana is hung from the ceiling? The data show results of an experiment with 11 bananas that are hung from the ceiling. Assume that that distribution of the population is normal. 5.3, 6, 5.5, 7, 5.4, 5.7, 6.2, 6.4, 9.1, 8.7, 8.3 What can be concluded at the the a = 0.01 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ?v Select an answerv H: ?vSelect an answerv C. The test statistic ?v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ?v a f. Based on this, we should Select an answerv the null hypothesis. R. Thus, the final conclusion is that 2
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The accompanying histogram shows the lengths of hospital stays (in days) for all female patients admitted to a certain hospital during one year with a primary diagnosis of acute myocardial infarction (heart attack). Complete parts (a) through (c) below. a) From the histogram, determine whether the mean or median is larger. Explain. A. Because the distribution is nearly symmetric, the mean is expected to be larger than the median. B. Because the distribution is nearly symmetric, the mean is expected to be about the same as the median. C. Because the distribution is skewed to the high end, the mean is expected to be larger than the median. D. Because the distribution is skewed to the high end, the mean is expected to be smaller than the median. E. Because the distribution is skewed to the low end, the mean is expected to be larger than the median. F. Because the distribution is skewed to the low end, the mean is expected to be…
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