**Title: Analyzing the Reaction of 2-Methyl-2-butene with HBr****Objective:**To understand and predict the product(s) formed when 2-methyl-2-butene reacts with HBr.**Reaction Details:**- **Starting Material:** - Structure: 2-Methyl-2-butene - Description: This is an unsaturated hydrocarbon (alkene) featuring a double bond between the second and third carbon atoms.- **Reagent:** - Hydrogen Bromide (HBr)**Expected Reaction:**When 2-methyl-2-butene is treated with HBr, a hydrohalogenation reaction occurs. This type of reaction involves the addition of hydrogen (H) and a halogen (Br) across the double bond.**Mechanism Overview:**1. **Protonation of the Double Bond:** - The double bond is protonated by HBr, leading to the formation of a carbocation intermediate. Due to Markovnikov's rule, the proton attaches to the less substituted carbon, resulting in a more stable carbocation.2. **Carbocation Stability:** - In this reaction, the most stable carbocation is the tertiary carbocation resulting from the protonation at the less substituted end of the double bond.3. **Nucleophilic Attack:** - The bromide ion (Br-) then attacks the carbocation, leading to the formation of the final product.**Final Product:**- The major product of this reaction is 2-bromo-2-methylbutane, where the bromine atom is added to the carbon atom that was part of the original double bond, in accordance with Markovnikov's rule.**Conclusion:**This reaction is a classic example of electrophilic addition involving alkenes and illustrates the application of Markovnikov's rule, which predicts the regiochemistry of the addition of hydrogen halides to unsymmetrical alkenes.

Answer) Markovnikov's addition mechanism is follwed . There is form haloalkane by carbocation…

Answered: HBr | bartleby

Science

Chemistry

HBr

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Group 15 elements

The elements of group 15 are phosphorus, nitrogen, bismuth antimony, and arsenic. The most abundant element which is present in the air is nitrogen and the percentage of nitrogen present in the air is 78%. In the free state, the elemental nitrogen is present as diatomic gas (N2). In the organic matter obtained from plants and animals, phosphorus is the dominant element present. In nucleic acids, phosphate groups are present. Phosphates are also found in teeth and bones. The other elements arsenic, bismuth, and antimony are found as sulfides. Arsenopyrite, bismuth glance, and stibnite are examples of sulfides of arsenic, bismuth, and antimony respectively.

Question

**Title: Analyzing the Reaction of 2-Methyl-2-butene with HBr**

**Objective:**
To understand and predict the product(s) formed when 2-methyl-2-butene reacts with HBr.

**Reaction Details:**

- **Starting Material:**
- Structure: 2-Methyl-2-butene
- Description: This is an unsaturated hydrocarbon (alkene) featuring a double bond between the second and third carbon atoms.

- **Reagent:**
- Hydrogen Bromide (HBr)

**Expected Reaction:**

When 2-methyl-2-butene is treated with HBr, a hydrohalogenation reaction occurs. This type of reaction involves the addition of hydrogen (H) and a halogen (Br) across the double bond.

**Mechanism Overview:**

1. **Protonation of the Double Bond:**
- The double bond is protonated by HBr, leading to the formation of a carbocation intermediate. Due to Markovnikov's rule, the proton attaches to the less substituted carbon, resulting in a more stable carbocation.

2. **Carbocation Stability:**
- In this reaction, the most stable carbocation is the tertiary carbocation resulting from the protonation at the less substituted end of the double bond.

3. **Nucleophilic Attack:**
- The bromide ion (Br-) then attacks the carbocation, leading to the formation of the final product.

**Final Product:**
- The major product of this reaction is 2-bromo-2-methylbutane, where the bromine atom is added to the carbon atom that was part of the original double bond, in accordance with Markovnikov's rule.

**Conclusion:**

This reaction is a classic example of electrophilic addition involving alkenes and illustrates the application of Markovnikov's rule, which predicts the regiochemistry of the addition of hydrogen halides to unsymmetrical alkenes.

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