I have the question and the answer for this problem I just want to understand the concepts and logic of how to do it step by step Write a complete program that will divide a given amount of liquid (in fluid ounces) into gallons,quarts, pints, cups, and remaining ounces. There are 8 ounces in a cup, 2 cups in a pint, 2 pintsin a quart, and 4 quarts in a gallon. The input file will contain zero or more integer values thatrepresent the amount of liquid in fluid ounces. The input values are separated from each other bywhite space. Your program must do the following:1. Include all necessary library header files.2. Open and read from an input file called liquid.dat3. Open and write to a file called volume.out4. Echo print the input data.5. Print the message "Illegal input" if the input value is zero or negative.6. Continue to "loop back" and read from the input file until the end of file is reached.Example:Input File:733 -5Output File:Amount of liquid: 733 fluid ounce(s)5 gallon(s)2 quart(s)1 pint(s)1 cup(s)5 ounce(s)Amount of liquid: -5 fluid ounce(s)Illegal input#include void main() {int liquid;FILE *fin, *fout;fin=fopen("liquid.dat", "r");fout=fopen("volume.out", "w");while ( fscanf(fin, "%d", &liquid) > e ) {fprintf(fout, "Amount of liquid: %d fluid ounce(s)\n", liquid);if (liquid <= 0)fprintf(fout, "else {fprintf(fout,fprintf(fout, "fprintf(fout, "fprintf(fout, "fprintf(fout, "/* or != EOF /Illegal input \n");%d gallon(s)\n", liquid/128); liquid %= 128;%d quart(s)\n", liquid/32); liquid %= 32;%d pint(s)\n", liquid/16); liquid %= 16;%d cup(s)\n", liquid/8); liquid X= 8;%d ounce(s)\n", iiquid);

The program is correct and already very self explained. I am trying my best to explain in more clear…

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have the question and the answer for this problem I just want to understand the concepts and logic of how to do it step by step

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

I have the question and the answer for this problem I just want to understand the concepts and logic of how to do it step by step

Write a complete program that will divide a given amount of liquid (in fluid ounces) into gallons,
quarts, pints, cups, and remaining ounces. There are 8 ounces in a cup, 2 cups in a pint, 2 pints
in a quart, and 4 quarts in a gallon. The input file will contain zero or more integer values that
represent the amount of liquid in fluid ounces. The input values are separated from each other by
white space. Your program must do the following:
1. Include all necessary library header files.
2. Open and read from an input file called liquid.dat
3. Open and write to a file called volume.out
4. Echo print the input data.
5. Print the message "Illegal input" if the input value is zero or negative.
6. Continue to "loop back" and read from the input file until the end of file is reached.
Example:
Input File:
733 -5
Output File:
Amount of liquid: 733 fluid ounce(s)
5 gallon(s)
2 quart(s)
1 pint(s)
1 cup(s)
5 ounce(s)
Amount of liquid: -5 fluid ounce(s)
Illegal input
#include <stdio.h>
void main() {
int liquid;
FILE *fin, *fout;
fin=fopen("liquid.dat", "r");
fout=fopen("volume.out", "w");
while ( fscanf(fin, "%d", &liquid) > e ) {
fprintf(fout, "Amount of liquid: %d fluid ounce(s)\n", liquid);
if (liquid <= 0)
fprintf(fout, "
else {
fprintf(fout,
fprintf(fout, "
fprintf(fout, "
fprintf(fout, "
fprintf(fout, "
/* or != EOF /
Illegal input \n");
%d gallon(s)\n", liquid/128); liquid %= 128;
%d quart(s)\n", liquid/32); liquid %= 32;
%d pint(s)\n", liquid/16); liquid %= 16;
%d cup(s)\n", liquid/8); liquid X= 8;
%d ounce(s)\n", iiquid);

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