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have the question and the answer for this problem I just want to understand the concepts and logic of how to do it step by step

have the question and the answer for this problem I just want to understand the concepts and logic of how to do it step by step

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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I have the question and the answer for this problem I just want to understand the concepts and logic of how to do it step by step

 

Write a complete program that will divide a given amount of liquid (in fluid ounces) into gallons, quarts, pints, cups, and remaining ounces. There are 8 ounces in a cup, 2 cups in a pint, 2 pints in a quart, and 4 quarts in a gallon. The input file will contain zero or more integer values that represent the amount of liquid in fluid ounces. The input values are separated from each other by white space. Your program must do the following: 1. Include all necessary library header files. 2. Open and read from an input file called liquid.dat 3. Open and write to a file called volume.out 4. Echo print the input data. 5. Print the message "Illegal input" if the input value is zero or negative. 6. Continue to "loop back" and read from the input file until the end of file is reached. Example: Input File: 733 -5 Output File: Amount of liquid: 733 fluid ounce(s) 5 gallon(s) 2 quart(s) 1 pint(s) 1 cup(s) 5 ounce(s) Amount of liquid: -5 fluid ounce(s) Illegal input #include <stdio.h> void main() { int liquid; FILE *fin, *fout; fin=fopen("liquid.dat", "r"); fout=fopen("volume.out", "w"); while ( fscanf(fin, "%d", &liquid) > e ) { fprintf(fout, "Amount of liquid: %d fluid ounce(s)\n", liquid); if (liquid <= 0) fprintf(fout, " else { fprintf(fout, fprintf(fout, " fprintf(fout, " fprintf(fout, " fprintf(fout, " /* or != EOF / Illegal input \n"); %d gallon(s)\n", liquid/128); liquid %= 128; %d quart(s)\n", liquid/32); liquid %= 32; %d pint(s)\n", liquid/16); liquid %= 16; %d cup(s)\n", liquid/8); liquid X= 8; %d ounce(s)\n", iiquid);
Transcribed Image Text:Write a complete program that will divide a given amount of liquid (in fluid ounces) into gallons, quarts, pints, cups, and remaining ounces. There are 8 ounces in a cup, 2 cups in a pint, 2 pints in a quart, and 4 quarts in a gallon. The input file will contain zero or more integer values that represent the amount of liquid in fluid ounces. The input values are separated from each other by white space. Your program must do the following: 1. Include all necessary library header files. 2. Open and read from an input file called liquid.dat 3. Open and write to a file called volume.out 4. Echo print the input data. 5. Print the message "Illegal input" if the input value is zero or negative. 6. Continue to "loop back" and read from the input file until the end of file is reached. Example: Input File: 733 -5 Output File: Amount of liquid: 733 fluid ounce(s) 5 gallon(s) 2 quart(s) 1 pint(s) 1 cup(s) 5 ounce(s) Amount of liquid: -5 fluid ounce(s) Illegal input #include <stdio.h> void main() { int liquid; FILE *fin, *fout; fin=fopen("liquid.dat", "r"); fout=fopen("volume.out", "w"); while ( fscanf(fin, "%d", &liquid) > e ) { fprintf(fout, "Amount of liquid: %d fluid ounce(s)\n", liquid); if (liquid <= 0) fprintf(fout, " else { fprintf(fout, fprintf(fout, " fprintf(fout, " fprintf(fout, " fprintf(fout, " /* or != EOF / Illegal input \n"); %d gallon(s)\n", liquid/128); liquid %= 128; %d quart(s)\n", liquid/32); liquid %= 32; %d pint(s)\n", liquid/16); liquid %= 16; %d cup(s)\n", liquid/8); liquid X= 8; %d ounce(s)\n", iiquid);
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