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have 3), 5(2 (A, E) and the size (i.e., the number of rows) of each relation is as follows: TR = 1000, rs = 3000, TT= 4000, TU = 2000. so, assume that all attributes of the relations are of the same length and we use hash join, so the st of joining X € {R, S, T, U} and Y = {R, S, T, U} is approximately: k(rx.cx+ry.cy) here k is a constant, rx and cx denote the number of rows and the number of columns of , respectively, and ry and cy denote the number of rows and the number of columns of Y. nally, assume that the size of a join is always 0.2% of the size of the cross product (i.e., TXY = 02. TX.TY). Under the above assumptions, find the lowest cost plan for computing R▷ S▷ T▷ U using mamic programming and left-deep join trees. You need to complete the following table while ding the best plans (e.g., in the form of ((□ □) □) □ in the last line) and associated costs. Cost Subquery RAS RAT RAU SAT SAU TAU RASAT RASAU RATAU SAT U BAS TAU Size Best Plan 6000 8000k (1000-2 +3000 - 2)k] || R&S

have 3), 5(2 (A, E) and the size (i.e., the number of rows) of each relation is as follows: TR = 1000, rs = 3000, TT= 4000, TU = 2000. so, assume that all attributes of the relations are of the same length and we use hash join, so the st of joining X € {R, S, T, U} and Y = {R, S, T, U} is approximately: k(rx.cx+ry.cy) here k is a constant, rx and cx denote the number of rows and the number of columns of , respectively, and ry and cy denote the number of rows and the number of columns of Y. nally, assume that the size of a join is always 0.2% of the size of the cross product (i.e., TXY = 02. TX.TY). Under the above assumptions, find the lowest cost plan for computing R▷ S▷ T▷ U using mamic programming and left-deep join trees. You need to complete the following table while ding the best plans (e.g., in the form of ((□ □) □) □ in the last line) and associated costs. Cost Subquery RAS RAT RAU SAT SAU TAU RASAT RASAU RATAU SAT U BAS TAU Size Best Plan 6000 8000k (1000-2 +3000 - 2)k] || R&S

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Assume that we have four relations R(A, B), S(A,C), T(A,D) and U(A, E) and the size (i.e., the number of rows) of each relation is as follows: 3000, TT= 4000, ru 2000. TR = 1000, rs = Also, assume that all attributes of the relations are of the same length and we use hash join, so the cost of joining X € {R, S, T, U} and Y € {R, S, T, U} is approximately: k(rx cx+ry CY) where k is a constant, rx and cx denote the number of rows and the number of columns of X, respectively, and ry and cy denote the number of rows and the number of columns of Y. Finally, assume that the size of a join is always 0.2% of the size of the cross product (i.e., rx=y= 0.002.TX.TY). Under the above assumptions, find the lowest cost plan for computing R▷ S▷ T▷ U using dynamic programming and left-deep join trees. You need to complete the following table while finding the best plans (e.g., in the form of ((O)) in the last line) and associated costs. Subquery RAS RAT RAU SAT SAU TAU RAST RASAU RATAU SATAU R S T U Size 6000 8000k Cost Best Plan [= (1000-2+ 3000-2)k] RS
Transcribed Image Text:Assume that we have four relations R(A, B), S(A,C), T(A,D) and U(A, E) and the size (i.e., the number of rows) of each relation is as follows: 3000, TT= 4000, ru 2000. TR = 1000, rs = Also, assume that all attributes of the relations are of the same length and we use hash join, so the cost of joining X € {R, S, T, U} and Y € {R, S, T, U} is approximately: k(rx cx+ry CY) where k is a constant, rx and cx denote the number of rows and the number of columns of X, respectively, and ry and cy denote the number of rows and the number of columns of Y. Finally, assume that the size of a join is always 0.2% of the size of the cross product (i.e., rx=y= 0.002.TX.TY). Under the above assumptions, find the lowest cost plan for computing R▷ S▷ T▷ U using dynamic programming and left-deep join trees. You need to complete the following table while finding the best plans (e.g., in the form of ((O)) in the last line) and associated costs. Subquery RAS RAT RAU SAT SAU TAU RAST RASAU RATAU SATAU R S T U Size 6000 8000k Cost Best Plan [= (1000-2+ 3000-2)k] RS
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