Hashing is a technique to convert a range of key values into a range of indexes of an array. Load Factor is a measure of how full the hash table is allowed to get before its capacity is automatically increased which may cause a collision. When collision occurs, there are two simple solutions: Chaining and Linear Probe. In what order could the elements have been added using the output below and given the following hash table implemented using linear probing. Note the following: A B C D E 1. The hash function used is the identity function, h(x) = x. 2. Assume that the hash table has never been resized, and no elements have been deleted yet. 3. There are several correct answers 4. Show all workings 0 1 2 3 18 O 4 12 3 9, 14, 4, 18, 12, 3, 21 12, 3, 14, 18, 4, 9, 21 12, 14, 3, 9, 4, 18, 21 9, 12, 14, 3, 4, 21, 18 12, 9, 18, 3, 14, 21, 4 5 6 4 14 7 8 21

Hashing is a technique to convert a range of key values into a range of indexes of an array. Load Factor is a measure of how full the hash table is allowed to get before its capacity is automatically increased which may cause a collision. When collision occurs, there are two simple solutions: Chaining and Linear Probe. In what order could the elements have been added using the output below and given the following hash table implemented using linear probing. Note the following: A B C D E 1. The hash function used is the identity function, h(x) = x. 2. Assume that the hash table has never been resized, and no elements have been deleted yet. 3. There are several correct answers 4. Show all workings 0 1 2 3 18 O 4 12 3 9, 14, 4, 18, 12, 3, 21 12, 3, 14, 18, 4, 9, 21 12, 14, 3, 9, 4, 18, 21 9, 12, 14, 3, 4, 21, 18 12, 9, 18, 3, 14, 21, 4 5 6 4 14 7 8 21

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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3. Double hashing is one of the methods to resolve collision. Write a function to implement this method. The equations used in this method are given below. Note: implement everything within the double hash function. P = (P + INCREMENT(Key)) mod TABLE_SIZE INCREMENT(Key) = 1 + (Key mod INCR)
Course: Data Structure and Algorithms Language: Java Kindly something and Answer in 1 hour. Read Carefully and give answer with all necesary details. See the image for askii codes. Question6: In this Problem, you are required to insert some keys into a hash table, using given hash functions. You have to Draw a Hash table with the inserted keys. Write total number of collisions encountered when a particular collision resolution technique is used. size= 13, H(X) = sum of Ascii codes of key % HTSIZE Keys: Mia, Bea, Zoe, Jan, Ada, Sam, Leo, Meo, Ben, Tim, Ted, Zod Use Linear probing: H’(X) = [H(X) +f(i))] % HTSIZE where f(i)=i where i=0,1,2,….
Draw the contents of the hash table given the following conditions: The size of the hash table is 25. • Linear Probing is used to resolve collisions. • The hash function H(k) should be calculated in the following way where k is the element to be hashed: R(k) = k mod (summation of last two digits of your student id + 7) If R(k)<10 H(k)=R(k) + 8 else H(k)=R(k) - 4 What values will be in the hash table after the following sequence of insertions? 55, 65, 8, 18, 20, 11, 56, 27, 15, 167 [Note: Draw the values using a hash table and show your work for partial credit.]
Generate 11 unique random elements and perform the extendible hashing. The bucket size is three (3) and the Hash function is the following: H(X) => Suppose the global depth is X. Then the Hash Functi9on returns X LSBs. Make sure that in every hashing step there is an equivalent explanation.
hash table
1. Suppose you use hashing with separate chaining. The array is size 7, and the hashing function is hash(k) = k % 7. What is the result of putting these keys into the hash table in this order: 18, 11, 20, 12, 22, 25. 2A. Repeat Question 1, but using hashing with linear probing instead. Don't resize. B. Suppose we have put these keys in Question 2A. What is the result if we now delete 18?
Consider the following scenario/assumptions: . A hash table can store at most 11 elements. Indices are numbered from 0 to 10. It is currently empty (no elements yet). • The hashing function is defined as H(k) = k % 11 . The collision resolution technique is Linear Probing. Insert the following keys in the hash table in the sequence that they appear below: • 172458 • 282459 • 392458 • 502461 • 612458 • 722463 832458 • 942465 1052458 • 1162467 Write on a piece of paper the contents of the resulting has table after inserting these keys. The table should contain 10 elements, with only one address that is left open, i.e., it is not occupied by any key. Answer the questions below by filling up the blanks, 1. What is the address (array index) of the memory space that is still open? 2. What is H(722463)? 3. In which address (array index) was key 832458 stored? 4. Which key value was stored in address (array index) 8? 5. The value of H(k) is called k's home address. How many keys were not…
We are using a subpar hash map, where each value is accumulated in a single container. A hash map has successfully achieved its purpose.
Draw the contents of the hash table given the following conditions: • The size of the hash table is 18. • Linear Probing is used to resolve collisions. • The hash function H(k) should be calculated in the following way where k is the element to be hashed: R(k) = k mod (summation of last two digits of your student id) If R(k)<10 H(k)=R(k)+8 else H(k)=R(k)-2 What values will be in the hash table after the following sequence of insertions? 35, 18, 8, 13, 11, 49, 16, 27 [Note: Draw the values using a hash table and show your work for partial credit.]
Case study: An event company asks you to design the data structure and program prototype for their running event system. The participant for the running event is expected to reach more than 1000 in various categories. You decided to use hashing function method to store the information for each participant's BIB number in the hash table. To begin the problem solving, suppose that 10 registered runners need to be stored in a hash table, HT, with a size of 13. The sample BIB number of the runners are: 101, 102, 103, 104, 107, 111, 121, 217, 157, and 185. Furthermore, you set the hash function to determine the index of the participant in the HT as: hash (BIB) = BIB % table size (or 13) However, if the hash index given by hash(BIB) is already occupied (collision), the linear probing hash function will be used as: hash (BIB) = (Hash (BIB)+1) % 17 and, further collision with hash function: hash (BIB) = (Hash(BIB)+2) % 17 or, hash(BIB) = (Hash (BIB) + n) % 17, where n is probe increment. Refer…
implementing a hash table When removing an item from my hashtable and leaving a tombstone, I understand that the tombstone must be a different data type from the rest of the elements in the hashtable, but how do I deal with type miss match error when trying to leave a tombstone?
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