hases, and compound X will be found dissolved in both the eth ow compound X distributes behan^^ .. Extraction as a Separation Tool Balance the euations Organic compounds fall into three broad classes: organic acids (carboxylic acids and phenols) . organic bases (amines) neutral (esters, ketones, aldehydes, ethers, etc) Organic acids, organic bases, and neutral organic compounds can be readily separated from each other on the basis of their acid-base characteristics. Organic acids (carboxylic acids and phenols) readily react with alkali bases (NaOH, KOH) to form water soluble organic acid salts (ionic compounds) он NaOH O Na benzoic acid, pka = 4。19 (a carboxylic acid) sodium benzoate (a salt of a carboxylic acid) a covalent organic compound soluble organic solvents, insoluble water an ionic organic compound insoluble organic solvents, soluble water
hases, and compound X will be found dissolved in both the eth ow compound X distributes behan^^ .. Extraction as a Separation Tool Balance the euations Organic compounds fall into three broad classes: organic acids (carboxylic acids and phenols) . organic bases (amines) neutral (esters, ketones, aldehydes, ethers, etc) Organic acids, organic bases, and neutral organic compounds can be readily separated from each other on the basis of their acid-base characteristics. Organic acids (carboxylic acids and phenols) readily react with alkali bases (NaOH, KOH) to form water soluble organic acid salts (ionic compounds) он NaOH O Na benzoic acid, pka = 4。19 (a carboxylic acid) sodium benzoate (a salt of a carboxylic acid) a covalent organic compound soluble organic solvents, insoluble water an ionic organic compound insoluble organic solvents, soluble water
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the proper way to balance an the reaction of benzoic acid with sodium hydroxide to form sodium benzoate?
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