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has a solubility constant of Ksp = 2.34 x 10-5⁹, and dissociates according to Hydroxyapatite, Ca₁0(PO4)(OH)₂, Ca₁0(PO4)6(OH)₂ (s) = 10 Ca² (aq) + 6 PO3(aq) + 2OH(aq) Solid hydroxyapatite is dissolved in water to form a saturated solution. What is the concentration of Ca²+ in this solution if [OH-] is fixed at 6.20 x 10-4 M?

has a solubility constant of Ksp = 2.34 x 10-5⁹, and dissociates according to Hydroxyapatite, Ca₁0(PO4)(OH)₂, Ca₁0(PO4)6(OH)₂ (s) = 10 Ca² (aq) + 6 PO3(aq) + 2OH(aq) Solid hydroxyapatite is dissolved in water to form a saturated solution. What is the concentration of Ca²+ in this solution if [OH-] is fixed at 6.20 x 10-4 M?

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Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Hydroxyapatite, Ca₁(PO)(OH)₂, Ca₁(PO4)(OH)₂ (s) ⇒ 10 Ca² ¹(aq) + 6PO³(aq) + 2OH(aq) has a solubility constant of Ksp = 2.34 × 10-5⁹, and dissociates according to 10 Solid hydroxyapatite is dissolved in water to form a saturated solution. What is the concentration of Ca²+in this solution if [OH-] is fixed at 6.20 x 10-4 M?
Transcribed Image Text:Hydroxyapatite, Ca₁(PO)(OH)₂, Ca₁(PO4)(OH)₂ (s) ⇒ 10 Ca² ¹(aq) + 6PO³(aq) + 2OH(aq) has a solubility constant of Ksp = 2.34 × 10-5⁹, and dissociates according to 10 Solid hydroxyapatite is dissolved in water to form a saturated solution. What is the concentration of Ca²+in this solution if [OH-] is fixed at 6.20 x 10-4 M?
Expert Solution
Step 1

The dissociation equation of hydroxyapatite, Ca10(PO4)6(OH)2(s) is:

Ca10(PO4)6(OH)2(s) ⇌  10Ca2+(aq) + 6PO43-(aq) + 2OH-(aq) ; Ksp = 2.34*10-59 

Given the [OH-(aq)] = 6.20*10-4 M 

 

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