Harris book: 27-11. To find the Ce4+ content of a solid, 4.37 g were dissolved and treated with excess iodate to precipitate Ce(IO,)4. The precipi- tate was collected, washed well, dried, and ignited to produce 0.104 g of CeO, (FM 172.114). What was the weight percent of Ce in the original solid?
Harris book: 27-11. To find the Ce4+ content of a solid, 4.37 g were dissolved and treated with excess iodate to precipitate Ce(IO,)4. The precipi- tate was collected, washed well, dried, and ignited to produce 0.104 g of CeO, (FM 172.114). What was the weight percent of Ce in the original solid?
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A problem and its solution is attached. Please explain each step for me to understand better. (Also, please explain why the moles of CeO2 and moles of Ce is equal to each other)
Transcribed Image Text:Harris book:
27-11. To find the Ce4+ content of a solid, 4.37 g were dissolved
and treated with excess iodate to precipitate Ce(IO,)4. The precipi-
tate was collected, washed well, dried, and ignited to produce 0.104 g
of CeO, (FM 172.114). What was the weight percent of Ce in the
original solid?
Transcribed Image Text:The Porecipitate of ce( Iog)y i ignited 40 Produce
4
O- 104 g Celz (FM 172.11y
Number of moles of CeOz ins
0. 104 8
172.114 8/mul
* 6. 8425 x10-4 meles.
6. O425 x10"4
CeOz
6.0425 x10-" male ce
Atomic mass of Ce
ILI0. 116
6.0425X10-u mal ce =
(6.0425 x10ml4
x IL10.116) ce
: O. 08 LI6 { ce
0.0846 g Ce ,
we got
forom 4.37 g solid.
: % of ce in sid:
O- 0846
= 1.935 o
X 100
4.37
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