Hans pulls a large crate across a horizontal floor as shown below. He pulls with a constant force of 450 N directed at 38° above the horizontal. A kinetic friction force of 125 N opposes the motion of the crate. What is the net work done on the crate, if it is pulled through a distance of 15 m?
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- Bob is pulling a box of his toys of mass 15.0 kg along a rough horizontal surface for a distance of 6.00 m. The tension force in the rope is 58.0 N and the angle is 30° with respect to the horizontal. The frictional force on the box is 12.0 N. How much work is done on the box by the normal force, in Joule? Use g = 10.0 m/s2. Your answer needs to have 3 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.A man pulls a 4.6-kg sled 50 meters along an angled hill with a force of 36 N, which elevates the man 28 meters above the bottom of the hill. The man then hops on his sled and slides from rest to the bottom of the hill back along his 50 meter path, during which a 299 N frictional force acts upon his sled. How much work in Joules does the man do against friction in pulling the sled up the hill?The graph (attached) shows the x component of a force that acts on an object that moves on the x axis. The vertical spacing between adjacent grid lines is 2.75 N, while the horizontal spacing between adjacent grid lines is 1.0 m. What is the work done by the force, in joules, as the object moves from x=1m to x=8m?
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- A sled with total mass m = 46.3 kg is pulled a distance d = 17.1 m across a horizontal surface for which the corficcient of kinetic friction with the sled is = 0.196. The pulling force is constant and makes an angle = 31.2° above the horizontal and the sled moves at a constant velocity. Find an expression for the work done by the pulling force in terms of m, acceleration due to gravity g, 0, Hk, and d, and use it find the work done in Joules by the pulling force. Find an expression for the work done on the sled by friction in terms of m, acceleration due to gravity g, 8, HK, and d, and use it to find the work done in Joules by the friction force. What is the net work in Joules done on the sled?A mother pulls her child on a sled across a rough patch of snow. The sled and child have a combined mass of 25kg. The sled’s tow rope is at 42° angle above the horizontal and the mother exerts a force of 65N. If the sled accelerates from rest at 1.5 m/s2 over 15m, what is the work done by friction on the sled?The spring-flex exercise system consists of a spring with one end fixed and a handle on the other end. The idea is that you exercise your muscles by stretching the spring from its natural length, which is 38 cm. If a 170 Newton force is required to keep the spring stretched to a length of 52 cm, how much work is required to stretch it from 51 cm to 70 cm? Your answer must include the correct units. Work =