Hans has 360 meters of fencing. He will use it to form three sides of a rectangular garden. The fourth side will be along a house and will not need fencing. As shown below, one of the sides has length x (in meters). Side along house (a) Find a function that gives the area A (x) of the garden (in square meters) in terms of x. A(:) = 0 (b) What side length x gives the maximum area that the garden can have? Side length x : meters (c) What is the maximum area that the garden can have? Maximum area: square meters

Elementary Geometry For College Students, 7e
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Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
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**Optimizing the Area of a Rectangular Garden with Limited Fencing**

Hans has 360 meters of fencing. He will use it to form three sides of a rectangular garden. The fourth side will be along a house and will not need fencing.

**Diagram Description:**
The diagram shows a rectangular garden with one side labeled as \( x \) which is aligned along the house. The remaining three sides are fenced, and the length of the two sides perpendicular to \( x \) is unknown.

**Problem Statements and Questions:**

(a) **Find a function that gives the area \( A(x) \) of the garden (in square meters) in terms of \( x \).**

\[ A(x) = \_\_\_\_ \]

(b) **What side length \( x \) gives the maximum area that the garden can have?**

\[ \text{Side length } x = \_\_\_\_ \text{ meters} \]

(c) **What is the maximum area that the garden can have?**

\[ \text{Maximum area} = \_\_\_\_ \text{ square meters} \]

**Explanation:**

To solve this problem, we need to derive the mathematical function for the area of the rectangular garden using the given fencing condition, optimize that function to find the value of \( x \) that maximizes the area, and finally calculate the maximum area.

1. **Deriving the Area Function:**
   - The total length of the fence used for the three sides is 360 meters.
   - The garden has one side along the house with length \( x \) and the other two sides are equal in length, let's call this length \( y \).
   - Therefore, the total fencing used is:

\[ x + 2y = 360 \]

\[ y = \frac{360 - x}{2} \]

   - The area \( A \) of the rectangle is given by the product of its length and width:

\[ A(x) = x \cdot y \]

Substituting the value of \( y \):

\[ A(x) = x \cdot \frac{360 - x}{2} \]

\[ A(x) = \frac{360x - x^2}{2} \]

\[ A(x) = 180x - \frac{x^2}{2} \]

2. **Finding the Maximum Area:**
   - To find the maximum area, we
Transcribed Image Text:**Optimizing the Area of a Rectangular Garden with Limited Fencing** Hans has 360 meters of fencing. He will use it to form three sides of a rectangular garden. The fourth side will be along a house and will not need fencing. **Diagram Description:** The diagram shows a rectangular garden with one side labeled as \( x \) which is aligned along the house. The remaining three sides are fenced, and the length of the two sides perpendicular to \( x \) is unknown. **Problem Statements and Questions:** (a) **Find a function that gives the area \( A(x) \) of the garden (in square meters) in terms of \( x \).** \[ A(x) = \_\_\_\_ \] (b) **What side length \( x \) gives the maximum area that the garden can have?** \[ \text{Side length } x = \_\_\_\_ \text{ meters} \] (c) **What is the maximum area that the garden can have?** \[ \text{Maximum area} = \_\_\_\_ \text{ square meters} \] **Explanation:** To solve this problem, we need to derive the mathematical function for the area of the rectangular garden using the given fencing condition, optimize that function to find the value of \( x \) that maximizes the area, and finally calculate the maximum area. 1. **Deriving the Area Function:** - The total length of the fence used for the three sides is 360 meters. - The garden has one side along the house with length \( x \) and the other two sides are equal in length, let's call this length \( y \). - Therefore, the total fencing used is: \[ x + 2y = 360 \] \[ y = \frac{360 - x}{2} \] - The area \( A \) of the rectangle is given by the product of its length and width: \[ A(x) = x \cdot y \] Substituting the value of \( y \): \[ A(x) = x \cdot \frac{360 - x}{2} \] \[ A(x) = \frac{360x - x^2}{2} \] \[ A(x) = 180x - \frac{x^2}{2} \] 2. **Finding the Maximum Area:** - To find the maximum area, we
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