Hannah set her watch 11.75 seconds behind, and it falls behind another 5.5 seconds every day. How far behind is Hannah's watch if she last set it 5 days ago? seconds
Hannah set her watch 11.75 seconds behind, and it falls behind another 5.5 seconds every day. How far behind is Hannah's watch if she last set it 5 days ago? seconds
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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![### Solving Linear Equations: Word Problems
**Problem Statement:**
Hannah set her watch 11.75 seconds behind, and it falls behind another 5.5 seconds every day. How far behind is Hannah's watch if she last set it 5 days ago?
**Solution:**
To determine how far behind Hannah's watch is, follow these steps:
1. **Initial Time Behind:**
- Hannah's watch was initially set 11.75 seconds behind.
2. **Daily Time Lost:**
- Each day, the watch falls behind an additional 5.5 seconds.
3. **Time Lost Over Multiple Days:**
- For 5 days, calculate the total additional time lost:
\[
\text{Total additional time lost} = 5.5 \, \text{seconds/day} \times 5 \, \text{days} = 27.5 \, \text{seconds}
\]
4. **Total Time Behind After 5 Days:**
- Add the initial time behind to the total additional time lost:
\[
\text{Total time behind} = 11.75 \, \text{seconds} + 27.5 \, \text{seconds} = 39.25 \, \text{seconds}
\]
**Answer:**
- Hannah's watch is 39.25 seconds behind.
**Input Box:**
[ ] **seconds**
**Submit Button:**
[**Submit**]
This exercise helps to practice solving linear equation word problems by systematically breaking down the given information and calculating the desired result.
[Image Description: The screenshot shows a math problem from an educational website called IXL, where students solve linear equation word problems. The problem involves calculating how far behind a watch is after a certain period. Below the problem statement is a box for entering the answer and a "Submit" button to check the solution.]
For additional practice, make sure to understand how to set up and solve linear equations based on word problems by identifying the initial value and the rate of change over time.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbbddcb8c-1b25-4c9a-b40d-a5fe79d16dfd%2Fc0e89d99-60e4-43d9-b5a5-e69a18fd691f%2F2b89sg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Solving Linear Equations: Word Problems
**Problem Statement:**
Hannah set her watch 11.75 seconds behind, and it falls behind another 5.5 seconds every day. How far behind is Hannah's watch if she last set it 5 days ago?
**Solution:**
To determine how far behind Hannah's watch is, follow these steps:
1. **Initial Time Behind:**
- Hannah's watch was initially set 11.75 seconds behind.
2. **Daily Time Lost:**
- Each day, the watch falls behind an additional 5.5 seconds.
3. **Time Lost Over Multiple Days:**
- For 5 days, calculate the total additional time lost:
\[
\text{Total additional time lost} = 5.5 \, \text{seconds/day} \times 5 \, \text{days} = 27.5 \, \text{seconds}
\]
4. **Total Time Behind After 5 Days:**
- Add the initial time behind to the total additional time lost:
\[
\text{Total time behind} = 11.75 \, \text{seconds} + 27.5 \, \text{seconds} = 39.25 \, \text{seconds}
\]
**Answer:**
- Hannah's watch is 39.25 seconds behind.
**Input Box:**
[ ] **seconds**
**Submit Button:**
[**Submit**]
This exercise helps to practice solving linear equation word problems by systematically breaking down the given information and calculating the desired result.
[Image Description: The screenshot shows a math problem from an educational website called IXL, where students solve linear equation word problems. The problem involves calculating how far behind a watch is after a certain period. Below the problem statement is a box for entering the answer and a "Submit" button to check the solution.]
For additional practice, make sure to understand how to set up and solve linear equations based on word problems by identifying the initial value and the rate of change over time.
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