Half life of a radioactive isotope is 4x108 years. If there are 10³ radioactive nudei in a sample today, the number of such nuclei in the sample 4x10⁹ year ago were: (A)128 X10³ (B) 256X10³ (C) 512 X10³ (D) 1024 X10³
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Q: The half life for the decay of carbon-14 is 5.73*10^3 years. Suppose the activity due to the…
A: Half life of C-14 T1/2= yearsinitial activity of sample A0= BqActivity of sample At = Bq
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- The half-life of 1311 is 8.04 days. (a) Convert the half-life to seconds. S (b) Calculate the decay constant for this isotope. S-1 (c) Convert 0.570 μCi to the SI unit the becquerel. Bq (d) Find the number of 13¹1 nuclei necessary to produce a sample with an activity of 0.570 μCi. 1311 nuclei (e) Suppose the activity of a certain 13¹1 sample is 6.90 mCi at a given time. Find the number of half-lives the sample goes through in 40.2 d and the activity at the end of that period. (Enter your answer for the number of half-lives to at least one decimal place.) half-lives mCiCarbon-14, with a half-life of 5730 years, has a decay constant of λ = 1.21 × 10-4 yr-1. A piece of wood from an archaeological site is found to have 1.9 % of its original carbon-14. How many years old (t) is the piece of wood? Express your answer in scientific notation. Example: 1.23e4.The activity of a particular radioactive nuclide falls from 1 × 1011 Bq to 2 × 1010 Bq in 10 hours. Calculate the half-life of the nuclide.
- What fraction f1 of a radioactive sample will be left after 6 half‑lives? What fraction f2 of a radioactive sample will be left after 7.5 half‑lives?Use the fact that there are 3.13x107 s/year. (a) The half-life of the radioactive nucleus 22688Ra is 1.58x103 years. What is the decay constant (in s-1) of 22688Ra? (b) If a sample of 22688Ra nuclei has a decay rate of 3.9x105 decays /s at t = 0, then what is the decay rate after the sample is 4740 years old?The binding energy for a nucleus containing Z protons and N neutrons is defined as c²[ZM + Nm, - M] where M is the mass of the neutral atom containing the nucleus, the quantity in the parentheses is the mass defect, and c? = 931.5 MeV/u.The binding energy of a nuclide can also be written as E, = Am x 931.5 MeV/u where Am is the mass defect. The Figure below show the mass for neutral atom and the nucleons of a helium atom. SHe Binding energy Mass = 4.0026 u Mass = 4.0330 u Calculate the mass defect Am of a helium atom