хах 3. S cos (2-3x2)

Q: Sinxtsina3x COSX+ COS 32 tan 22

A:

Q: Cos20=2Cos 0-1

A: Part 1,Given,            cos2θ=2cos2θ-1

Q: 2. ( sin32x dx cos 2x

A: We have to integrate.

Q: If z = 2 ( cos 2¥/3 + isin 2¥/3 ), then z^3=   i. 2 - i8√3 ii. -4 + i4√3 iii.-8-i√2 iv. -8 - i4

A: Using de-moivre's formula :

Q: (1+cos3x)² -dx sin23x

A:

Q: tan 2x = √3/3

A: Trigonometric

Q: Express sin6 Oin terms of powers of sin Oonly

A: We have given,  sin6θ we have to express it in the term of sin only.

Q: t-a) Scin 3ada

A: L= ∫0t(t-a) sin3a da   =∫0tt sin3a da- ∫0ta sin3a da   =-t cos 3a3t0- a∫0t sin3a da+ ∫0t dada…

Q: sin- a. b. undefined cos(-210) C. Cus270 tan450 d.

A: sin17π6=cosπ2-17π6=cos-7π3=cos7π3=cosπ3=12        cos-210∘ =cos210∘ =-32

Q: (1+Sin O+COs02=a(+Sin0)+cose)

A:

Q: 9=3 Sin 2X 2.

A: answer is in next step

Q: Verify identity cos2 x - sin2 x = 2 cos2 x - 1.

A: cos2x -sin2x=2cos2x-1

Q: るn42 131 ダ= Acos6x+BtnGx-上を4: ginA: To

A:

Q: (1-sin9x)²dx

A: To evaluate the given integral

Q: 1+cos4x 1. 1-cos4x -csc2xdx

A:

Q: The value of (-1+√3 i)^(1/3) is О 2 exp((2TU/7)^i ) 2 exp((2/3)^i) 2 exp((2T/9)^i) 2 exp((2T/5)^i)…

A: We need to choose correct option. As per Bartleby's guidelines we can solve only one question from…

Q: The absolute values is T₁, x T. = = Vr¹ cos² usinv + r¹ sin² usin¹ v + r¹ cos² v sin² v r²(cos² u +…

A:

Q: 1- cos 18x 2

A: Given,          ±1-cos18x2

Q: 2Cos 2x- Sin20-2

A:

Q: 2(csc270°)+7(cos90°)^2+sec0°=

A: Solving by trigonometric ratios we have

Q: sec(품) 7π (a) 4 cos( - 2") (b) CoS an(- ) 11A (c) 6

A: