х(4+sin 6x) 3. lim X→+0 х+1

Q: limg-0 2x sinx 4-4cosx

A: We can find the limit as below, using L'Hospital rule.

Q: sin 5x 1. limx-0 2x2 +3x 2. limx→0 x3+x+1

A: 1).limx→0 sin 5xx2).limx→∞ 2x2 +3xx3 +x+1

Q: ) lim Sin (x3x+2) メーラー x3+1

A:

Q: (sinx -) tan*(5x) Q3/ 1)- lim, 2)- limx-0 (3sin?x -sinx +1) x sin3 (2x)

A: There are multiple question. As per Bartleby policy Kindly ask other question separately.  Given…

Q: 3 Lim x40 Cosx (2 Cos²x - 1) Cosx -

A:

Q: xª + x³ – 2x +1 Find lim 00 214 — Зх3 + 5x2 + 1'

A:

Q: 8 him XT 2 (secx tanx) 1

A:

Q: tan (5x) x sin3 (2x) 2)- limx-o:

A: we have to evaluate the A=limx→0tan4(5x)xsin3(2x)

Q: x+2 lim sin - x+6x+8 3 2.

A:

Q: 2-4x3 3. lim X→0- 5x²+3x³

A: To evaluate: limx→0-2-4x35x2+3x3

Q: 9. Simplify sec² x - 1 sec² x

A: secx=1cosxI=sec2x-1sec2xsin2x+cos2x=1

Q: Vx+1- /2x x² - x 2х f ) lim x→1

A: As per our guidelines we are suppose to solve only first question. Kindly repost the other question…

Q: lim

A:

Q: lim x→0 7x sin 4x

A:

Q: 9. Simplify 2 + tan² sec² x - 1.

A: Simplify

Q: 2х-п lim =? COSX 2

A: We can use differential calculus to find the solution. When we directly apply the limit we get an…

Q: 4x+sin x lim x→02x - sin 3x

A: We have to solve given problem:

Q: dx J x²–18x+97 O fIn (x² – 18x + 97) + C In (x² – 18x + 97) + C 0sin-l (부) + C х-9 O tan-' () + C…

A:

Q: X-yi/x2+y2=1/(1+xi)(3+i)

A: Given

Q: sin5x(1-2t)dt (6) lim

A: limx→0∫xsin5x1-2tdtx Let  I=∫xsin5x1-2tdt=t-t2xsin5x=sin5x-sin25x-x+x2

Q: lim 3X=12x→4

A: We can show this by substitution  We plug x=4

Q: 1. lim 2x+1 2. lim x→3 ズ-3 x-1 ミ- キ* さ

A:

Q: lim, 0 6 tan² (5x) 15x²

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Q: V1+tan x-V1+sin x Evaluate lim→0

A: Multiply the numerator and denominator by the conjugate of the numerator to simplify the expression.…

Q: lim (5x + 2) = 17x→3

A: We will find the limit by substitution

Q: [[+] [[P] [smal

A:

Q: 2 X-9 Sinx +34 2

A: Hi ! Thanks for posting your question. Since our portal allows to answer only first three questions,…

Q: +lim x-0 e -x - 8x ex - e x - sin x

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Q: 'sin 2x 18. lim X-\ sinx в 2 со R-2

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Q: lim (1 – 3x² )= x-2 а. -13 b. 11 С. 13 d. -11

A: By the linearity of limit of a function we can solve the given problem

Q: sin4x 15. lim x→0 sin7x

A: