[H3O*] = 5.33 x 107 pH = %3D %3D [OH]] = 1.33 x 109 pH = %3D %3D pH= 11.3 [H;O*] = %3D pOH= 5.46 [H;O*] =

Introductory Chemistry: A Foundation
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Chapter15: Solutions
Section: Chapter Questions
Problem 87QAP: 87. What volume of 0.151 N NaOH is required to neutralize 24.2 mL of 0.125 N H2SO4? What volume of...
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[H3O*] = 5.33 x 107
pH =
%3D
%3D
[OH]] = 1.33 x 109
pH =
%3D
%3D
pH= 11.3
[H;O*] =
%3D
pOH= 5.46 [H;O*] =
Transcribed Image Text:[H3O*] = 5.33 x 107 pH = %3D %3D [OH]] = 1.33 x 109 pH = %3D %3D pH= 11.3 [H;O*] = %3D pOH= 5.46 [H;O*] =
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