pH = - log [H30+1]pOH = - log [OH']pH + pOH = 14[H3O+1] = 10-pH[OH-1] = 10-pOH[H3O+1][OH-1] = 10-14%3D%3D%3D%3D%3DWhat is the pH of a solution with [OH1] = 5.55 x 10-5 M ?O A. 2.2437O B. 4.2557O C. 5.5000D. 5.7443O E. 9.7443

We have to calculate the pH of solution.

[H30+1] = 10-pH [OH-1] = 10-pOH [H3O+1][OH-1] = 10-14 pH = - log [H30+1] %3D %3D %3D pH + pOH = 14 %3D What is the pH of a solution with [OH1] = 5.55 x 10-5 M ? A. 2.2437 O B. 4.2557 O C. 5.5000 D. 5.7443 E. 9.7443

[H30+1] = 10-pH [OH-1] = 10-pOH [H3O+1][OH-1] = 10-14 pH = - log [H30+1] %3D %3D %3D pH + pOH = 14 %3D What is the pH of a solution with [OH1] = 5.55 x 10-5 M ? A. 2.2437 O B. 4.2557 O C. 5.5000 D. 5.7443 E. 9.7443

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

pH = - log [H30+1]
pOH = - log [OH']
pH + pOH = 14
[H3O+1] = 10-pH
[OH-1] = 10-pOH
[H3O+1][OH-1] = 10-14
%3D
%3D
%3D
%3D
%3D
What is the pH of a solution with [OH1] = 5.55 x 10-5 M ?
O A. 2.2437
O B. 4.2557
O C. 5.5000
D. 5.7443
O E. 9.7443

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