H2(g) + I2(g) → 2HI(g)I was given this problem:A student makes the following statements:Hydrogen always has the same oxidation number, so it has an oxidation number of +1 in both the reactant H2 and product HI.Iodine is in Group VIIA, so it has an oxidation number of –1 in both the reactant I2 and product HI.Neither hydrogen nor iodine changes oxidation states, so the reaction is not a redox reaction.How can I describe the mistake that the student made, and determine whether or not the reaction is a redox reaction.

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Answered: H2(g) + I2(g) → 2HI(g) I was given…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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H₂(g) + I₂(g) → 2HI(g)

I was given this problem:

A student makes the following statements:

Hydrogen always has the same oxidation number, so it has an oxidation number of +1 in both the reactant H₂ and product HI.
Iodine is in Group VIIA, so it has an oxidation number of –1 in both the reactant I₂ and product HI.
Neither hydrogen nor iodine changes oxidation states, so the reaction is not a redox reaction.

How can I describe the mistake that the student made, and determine whether or not the reaction is a redox reaction.

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