H2 Pd/C i. Br2 H20 j. H2 Pd/C k. Br2

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Draw the major product for the following reactions.
### Organic Reaction Diagrams:

**h.**
- **Reaction:**
  - A linear alkene is treated with hydrogen gas (H₂) in the presence of palladium on carbon (Pd/C) as a catalyst.
- **Process:**
  - This represents a hydrogenation reaction where the double bonds in the alkene are reduced to single bonds, resulting in an alkane.

---

**i.**
- **Reaction:**
  - A cyclopentene (a five-membered ring with a double bond) reacts with bromine (Br₂) in the presence of water (H₂O).
- **Process:**
  - This is a halogenation reaction where the double bond adds bromine, leading to the formation of a bromohydrin.

---

**j.**
- **Reaction:**
  - A branched alkene is treated with hydrogen gas (H₂) in the presence of palladium on carbon (Pd/C) as a catalyst.
- **Process:**
  - This is another example of hydrogenation. The double bonds of the alkene are reduced to single bonds, producing an alkane.

---

**k.**
- **Reaction:**
  - A branched alkene is treated with bromine (Br₂).
- **Process:**
  - This indicates a halogenation reaction where the pi bonds are broken and two bromine atoms are added across the double bond, forming a dibromo compound.

---

These diagrams demonstrate key organic reactions such as hydrogenation and halogenation, illustrating how double bonds can be manipulated to create various compounds.
Transcribed Image Text:### Organic Reaction Diagrams: **h.** - **Reaction:** - A linear alkene is treated with hydrogen gas (H₂) in the presence of palladium on carbon (Pd/C) as a catalyst. - **Process:** - This represents a hydrogenation reaction where the double bonds in the alkene are reduced to single bonds, resulting in an alkane. --- **i.** - **Reaction:** - A cyclopentene (a five-membered ring with a double bond) reacts with bromine (Br₂) in the presence of water (H₂O). - **Process:** - This is a halogenation reaction where the double bond adds bromine, leading to the formation of a bromohydrin. --- **j.** - **Reaction:** - A branched alkene is treated with hydrogen gas (H₂) in the presence of palladium on carbon (Pd/C) as a catalyst. - **Process:** - This is another example of hydrogenation. The double bonds of the alkene are reduced to single bonds, producing an alkane. --- **k.** - **Reaction:** - A branched alkene is treated with bromine (Br₂). - **Process:** - This indicates a halogenation reaction where the pi bonds are broken and two bromine atoms are added across the double bond, forming a dibromo compound. --- These diagrams demonstrate key organic reactions such as hydrogenation and halogenation, illustrating how double bonds can be manipulated to create various compounds.
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