h2 N(h) E 1" A uniform plane electromagnetic wave of frequency f= 5MHZ emitted by an antenna at the earth's surface is incident normally on a layer of the ionosphere whose concentration of free electrons can be approximated by the following linear function of the latitude above the earth's surface: (h – h,) N(h) = No (h2 – h1) For hjShSh2, where h=100 km, h=200 km and NF 5 x 10'' m³. Find the highest altitude h reached by the wave, at which it bounces off and returns to the antenna.
h2 N(h) E 1" A uniform plane electromagnetic wave of frequency f= 5MHZ emitted by an antenna at the earth's surface is incident normally on a layer of the ionosphere whose concentration of free electrons can be approximated by the following linear function of the latitude above the earth's surface: (h – h,) N(h) = No (h2 – h1) For hjShSh2, where h=100 km, h=200 km and NF 5 x 10'' m³. Find the highest altitude h reached by the wave, at which it bounces off and returns to the antenna.
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The expression for plasma frequency is sqrt(Ne^2/me*eps_0)
![th
h2
N(h)
h
A uniform plane electromagnetic wave of frequency f= 5MHZ emitted by an antenna at the earth's
surface is incident normally on a layer of the ionosphere whose concentration of free electrons can be
approximated by the following linear function of the latitude above the earth's surface:
(h – h,)
(h2 – h1)
-
N(h) = No
For hShSh2, where h=100 km, h;=200 km and No= 5 x 10" m³. Find the highest altitude h reached by
the wave, at which it bounces off and returns to the antenna.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fedbbbdd2-f33d-494b-9510-b218b96e9380%2F0e6846ba-9ae2-465b-beb6-366aa06c8221%2Ffznyh_processed.png&w=3840&q=75)
Transcribed Image Text:th
h2
N(h)
h
A uniform plane electromagnetic wave of frequency f= 5MHZ emitted by an antenna at the earth's
surface is incident normally on a layer of the ionosphere whose concentration of free electrons can be
approximated by the following linear function of the latitude above the earth's surface:
(h – h,)
(h2 – h1)
-
N(h) = No
For hShSh2, where h=100 km, h;=200 km and No= 5 x 10" m³. Find the highest altitude h reached by
the wave, at which it bounces off and returns to the antenna.
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