H2 (g) + 20 4. Calculate DH for the reaction 2 Al (s) +3 C12 (g)2 AIC13 (s) from the following data. 2 Al (s) +6 HCI (ag) →2 AICI3 (aq) + 3 H2 (g) AH = -1049. kJ HCI (g) - H2 (g) + C12 (g)→2 HCI (g) AICI3 (s) AIC13 (aq) - HCI (aq) AH = -74.8 kJ/mole AH = -1845. kJ AH = -323. kJ/mole

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter3: Chemical Reactions
Section: Chapter Questions
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Hi! Can someone answer Learning Task 4, no. 2? Thanks!
Learning Task 4:
Show your solution.
1. Calculate AH for the reaction 4 NH3 (g) + 5 02 (g) 4 NO (g) + 6 H2O (g), from the following data.
N2 (g) + 02 (g)→
N2 (g) +3 H2 (g)
2 H2 (g) + 02 (g) →2 H2O (g)
2 NO (g)
2 NH3 (g)
AH = -180.5 kJ
AH = -91.8 kJ
AH = -483.6 kJ
2. Find OHo for the reaction 2H2(g) + 2C(s) + 02(g) C2H5OH(I), using the following thermochemical data.
AH = -875 kJ
C2H5OH (I) +2 02 (g)2 CO2 (g) +2 H2O (I)
C (s) + 02 (g) →CO2 (g)
H2 (g) + ½ 02 (g) -
AH = -394.51 kJ
- H20 (I)
AH = -285.8 kJ
HCN (g) +3 H2 (g), given:
3. Calculate AH for the reaction CH4 (g) + NH3 (g) →
AH = -91.8 kJ
N2 (g) +3 H2 (g)2 NH3 (g)
C (s) +2 H2 (g)
H2 (g) + 2 C (s) + N2 (g) 2 HCN (g) AH = +270.3 kJ
AH = -74.9 kJ
- CH4 (g)
4. Calculate DH for the reaction 2 Al (s) +3 C12 (g)2 AIC13 (s) from the following data.
2 Al (s) +6 HCI (aq)2 AICI3 (aq) + 3 H2 (g) AH = -1049. kJ
HCI (g) HCI (aq)
H2 (g) + C12 (g)→2 HCI (g)
AICI3 (s)
AH = -74.8 kJ/mole
AH = -1845. kJ
AH = -323. kJ/mole
AIC13 (aq)
>
Transcribed Image Text:Learning Task 4: Show your solution. 1. Calculate AH for the reaction 4 NH3 (g) + 5 02 (g) 4 NO (g) + 6 H2O (g), from the following data. N2 (g) + 02 (g)→ N2 (g) +3 H2 (g) 2 H2 (g) + 02 (g) →2 H2O (g) 2 NO (g) 2 NH3 (g) AH = -180.5 kJ AH = -91.8 kJ AH = -483.6 kJ 2. Find OHo for the reaction 2H2(g) + 2C(s) + 02(g) C2H5OH(I), using the following thermochemical data. AH = -875 kJ C2H5OH (I) +2 02 (g)2 CO2 (g) +2 H2O (I) C (s) + 02 (g) →CO2 (g) H2 (g) + ½ 02 (g) - AH = -394.51 kJ - H20 (I) AH = -285.8 kJ HCN (g) +3 H2 (g), given: 3. Calculate AH for the reaction CH4 (g) + NH3 (g) → AH = -91.8 kJ N2 (g) +3 H2 (g)2 NH3 (g) C (s) +2 H2 (g) H2 (g) + 2 C (s) + N2 (g) 2 HCN (g) AH = +270.3 kJ AH = -74.9 kJ - CH4 (g) 4. Calculate DH for the reaction 2 Al (s) +3 C12 (g)2 AIC13 (s) from the following data. 2 Al (s) +6 HCI (aq)2 AICI3 (aq) + 3 H2 (g) AH = -1049. kJ HCI (g) HCI (aq) H2 (g) + C12 (g)→2 HCI (g) AICI3 (s) AH = -74.8 kJ/mole AH = -1845. kJ AH = -323. kJ/mole AIC13 (aq) >
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