a. The test statistic, t, is (Round to two decimal places as needed.)b. P-value (Round to three decimal places as needed.)c. Confidence interval (Round to three decimal places as needed.)d. conclusion for hypothesis test MenWomenA study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simplerandom samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a)and (b) below.H2n115997.27°F0.67°F97.59°F0.84°Fa. Use a 0.05 significance level to test the claim that men have a higher mean body temperature than women.What are the null and alternative hypotheses?A. Ho: H12 H2B. Ho: H1 =H2H1: H1 H2C. Ho: H1 # H2H1: 41

Answered: H2 A study was done on body…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Concept explainers

Question

a. The test statistic, t, is (Round to two decimal places as needed.)

b. P-value (Round to three decimal places as needed.)

c. Confidence interval (Round to three decimal places as needed.)

d. conclusion for hypothesis test

Men
Women
A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple
random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a)
and (b) below.
H2
n
11
59
97.27°F
0.67°F
97.59°F
0.84°F
a. Use a 0.05 significance level to test the claim that men have a higher mean body temperature than women.
What are the null and alternative hypotheses?
A. Ho: H12 H2
B. Ho: H1 =H2
H1: H1 <H2
H1: H1 > H2
C. Ho: H1 # H2
H1: 41 <H2
Họ: H1 = H2
H1: H1 # H2

Expert Solution

Step 1

(a) Calculation of the test statistic:

Formula:

$\begin{array}{rcl} t & = & \frac{{\bar{x}}_{1} - {\bar{x}}_{2}}{\sqrt{\frac{{s_{1}}^{2}}{n_{1}} + \frac{{s_{2}}^{2}}{n_{2}}}} \\ = & \frac{97.59 - 97.27}{\sqrt{\frac{0 . 84^{2}}{11} + \frac{0 . 67^{2}}{59}}} \\ = & \frac{0.32}{\sqrt{0.064145 + 0.007608}} \\ = & 1.1946 \\ \approx & 1.19 \end{array}$

Thus, the value of the test statistic is 1.19

Step by step

Solved in 2 steps

Knowledge Booster

$Basics of Inferential Statistics$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions