х2 —5х 5x 25

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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The following mathematical expression needs to be simplified:

\[ \frac{5}{x^2 - 5x} - \frac{x}{5x - 25} \]

In this equation, two rational expressions are being subtracted from each other. Each rational expression consists of a numerator and a denominator:

1. The first fraction: 
   - Numerator: 5
   - Denominator: \( x^2 - 5x \)

2. The second fraction:
   - Numerator: x
   - Denominator: \( 5x - 25 \)

To proceed with simplifying this expression, one may start by factoring the denominators.

### Factoring the Denominators

1. For the denominator \( x^2 - 5x \):
   \[ x^2 - 5x = x(x - 5) \]

2. For the denominator \( 5x - 25 \):
   \[ 5x - 25 = 5(x - 5) \]

### Simplified Expression

With these factorizations, the expression becomes:

\[ \frac{5}{x(x - 5)} - \frac{x}{5(x - 5)} \]

Combining the two fractions over a common denominator, which would be \( 5x(x - 5) \):

\[ \frac{5 \cdot 5 - x \cdot x}{5x(x - 5)} = \frac{25 - x^2}{5x(x - 5)} \]

### Final Notes

This simplified fraction can then be further analyzed or evaluated based on the specific values of \( x \), keeping in mind the restrictions where the denominator cannot be zero. In other words, \( x \neq 0 \) and \( x \neq 5 \) to avoid division by zero.
Transcribed Image Text:The following mathematical expression needs to be simplified: \[ \frac{5}{x^2 - 5x} - \frac{x}{5x - 25} \] In this equation, two rational expressions are being subtracted from each other. Each rational expression consists of a numerator and a denominator: 1. The first fraction: - Numerator: 5 - Denominator: \( x^2 - 5x \) 2. The second fraction: - Numerator: x - Denominator: \( 5x - 25 \) To proceed with simplifying this expression, one may start by factoring the denominators. ### Factoring the Denominators 1. For the denominator \( x^2 - 5x \): \[ x^2 - 5x = x(x - 5) \] 2. For the denominator \( 5x - 25 \): \[ 5x - 25 = 5(x - 5) \] ### Simplified Expression With these factorizations, the expression becomes: \[ \frac{5}{x(x - 5)} - \frac{x}{5(x - 5)} \] Combining the two fractions over a common denominator, which would be \( 5x(x - 5) \): \[ \frac{5 \cdot 5 - x \cdot x}{5x(x - 5)} = \frac{25 - x^2}{5x(x - 5)} \] ### Final Notes This simplified fraction can then be further analyzed or evaluated based on the specific values of \( x \), keeping in mind the restrictions where the denominator cannot be zero. In other words, \( x \neq 0 \) and \( x \neq 5 \) to avoid division by zero.
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