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Х1 + 2х2 + Зx3 — —7 2x1 – 3x2 – 5x3 = 9 — 6х1 — 8х2 + Хз 3— 22

Х1 + 2х2 + Зx3 — —7 2x1 – 3x2 – 5x3 = 9 — 6х1 — 8х2 + Хз 3— 22

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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How to solve using the inverse matrix method?

A. x1 + 2x2 + 3x3 = -7 = -7 2х1 — Зх2 — 5хз — 9 -6x1 – 8x2 + x3 = -22
Transcribed Image Text:A. x1 + 2x2 + 3x3 = -7 = -7 2х1 — Зх2 — 5хз — 9 -6x1 – 8x2 + x3 = -22
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