H.W.5: Determine i, io, and v, for all t in the circuit shown in Fig. 1. Assume that the switch was closed for a long time. It should be noted that opening a switch in series with an ideal current source creates an infinite voltage at the current source terminals. Clearly this is impossible. For the purposes of problem solving, we can place a shunt resistor in parallel with the source (which now makes it a voltage source in series with a resistor). In more practical circuits, devices that act like current sources are, for the most part, electronic circuits. These circuits will allow the source to act like an ideal current source over its operating range but voltage-limit it when the load resistor becomes too large (as in an open circuit). 12A t<0 (24V (8e-2v t>0 t<0 (6A 1-4e-2A t>0' t<0 Answer: i = 12e-2A t2 0' ww 1-0 1 H 18 A 40 Fig.1

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H.W.5: Determine i, i,, and v, for all t in the circuit shown in Fig.1. Assume that the switch was closed for a long
time. It should be noted that opening a switch in series with an ideal current source creates an infinite voltage at the
current source terminals. Clearly this is impossible. For the purposes of problem solving, we can place a shunt resistor
in parallel with the source (which now makes it a voltage source in series with a resistor). In more practical circuits,
devices that act like current sources are, for the most part, electronic circuits. These circuits will allow the source to
act like an ideal current source over its operating range but voltage-limit it when the load resistor becomes too large
(as in an open circuit).
12A
12e-2A t2 0'
(24V
(8e-2'v t>0
t<0
6A
t<0
t<0
Answer: i=
1-4e-2A t>0'
Vo =
32
ww
1-0
1 H
18A )
42
Fig.1
Transcribed Image Text:H.W.5: Determine i, i,, and v, for all t in the circuit shown in Fig.1. Assume that the switch was closed for a long time. It should be noted that opening a switch in series with an ideal current source creates an infinite voltage at the current source terminals. Clearly this is impossible. For the purposes of problem solving, we can place a shunt resistor in parallel with the source (which now makes it a voltage source in series with a resistor). In more practical circuits, devices that act like current sources are, for the most part, electronic circuits. These circuits will allow the source to act like an ideal current source over its operating range but voltage-limit it when the load resistor becomes too large (as in an open circuit). 12A 12e-2A t2 0' (24V (8e-2'v t>0 t<0 6A t<0 t<0 Answer: i= 1-4e-2A t>0' Vo = 32 ww 1-0 1 H 18A ) 42 Fig.1
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