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H.W. No.1 2nd semester Q-1: Given ; b= base width =14.5m, Flow depth=1.71m, channel longitudinal slope=S= 1:1175.5, n=0.0218. Find; Top width=T, Flow area =A, Wetted perimeter= P, Hydraulic radius= R, Flow velocity=V, and Q= Flow rate or discharge,

H.W. No.1 2nd semester Q-1: Given ; b= base width =14.5m, Flow depth=1.71m, channel longitudinal slope=S= 1:1175.5, n=0.0218. Find; Top width=T, Flow area =A, Wetted perimeter= P, Hydraulic radius= R, Flow velocity=V, and Q= Flow rate or discharge,

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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H.W. No.1 2nd semester Q-1: Given ; b= base width =14.5m, Flow depth=1.71m, channel longitudinal slope=S= 1:1175.5, n=0.0218. Find; Top width=T, Flow area =A, Wetted perimeter= P, Hydraulic radius= R, Flow velocity=V, and Q= Flow rate or discharge, T V= 4 y 2=V H or Z=10 4 =H or Z Answers are given below, solve and check. Send your detail solution with drawing. Top width=T= 22.1950m P=22.928m , Hydraulic radius=R= 1.3684m , Flow velocity=V= 0.5215m/sec, Q= Flow or discharge= 16.361m³/sec. Flow area =A = 32.374m², Wetted perimeter= Solve and send your detail solution Q-2. If discharge Q=6.9134 m³/sec, left side slope 5:3(H:V), Left side slope= 6:3, bed slope 2:8250, flow depth=y=1.8m, Bed width=b=10.55m. Find. Top width=T, Flow area =A, Wetted perimeter= P, Hydraulic radius= R, and Flow velocity=V. Draw and put all dimensions.
Transcribed Image Text:H.W. No.1 2nd semester Q-1: Given ; b= base width =14.5m, Flow depth=1.71m, channel longitudinal slope=S= 1:1175.5, n=0.0218. Find; Top width=T, Flow area =A, Wetted perimeter= P, Hydraulic radius= R, Flow velocity=V, and Q= Flow rate or discharge, T V= 4 y 2=V H or Z=10 4 =H or Z Answers are given below, solve and check. Send your detail solution with drawing. Top width=T= 22.1950m P=22.928m , Hydraulic radius=R= 1.3684m , Flow velocity=V= 0.5215m/sec, Q= Flow or discharge= 16.361m³/sec. Flow area =A = 32.374m², Wetted perimeter= Solve and send your detail solution Q-2. If discharge Q=6.9134 m³/sec, left side slope 5:3(H:V), Left side slope= 6:3, bed slope 2:8250, flow depth=y=1.8m, Bed width=b=10.55m. Find. Top width=T, Flow area =A, Wetted perimeter= P, Hydraulic radius= R, and Flow velocity=V. Draw and put all dimensions.
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