H.W 3.13 For the following relationship between z and y: 1+y+y²-y3 (1-y)³ What is the value of y if z = 0.892? Use the False-Position Method to solve for y. (Note: the value of y is between 0 and 3, correct to 4D and use €max = 0.08). Z= Answer: y = 1.9240

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Chapter2: Second-order Linear Odes
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H.W 3.13
For the following relationship between z and y:
1+ y + y²-y³
(1-y)³
What is the value of y if z = 0.892? Use the False-Position Method to solve for y.
(Note: the value of y is between 0 and 3, correct to 4D and use Emax = 0.08 ).
Z=
Answer: y = 1.9240
Transcribed Image Text:H.W 3.13 For the following relationship between z and y: 1+ y + y²-y³ (1-y)³ What is the value of y if z = 0.892? Use the False-Position Method to solve for y. (Note: the value of y is between 0 and 3, correct to 4D and use Emax = 0.08 ). Z= Answer: y = 1.9240
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