Can you explain how to get the domain and range as well as the transformation of the graph? it is not a reflection but an inverse?Please see attachment The equation presented is:\[ h(x) = e^{-x} - 5 \]This is a mathematical function where:- \( h(x) \) represents the output of the function for a given input \( x \).- \( e^{-x} \) indicates the exponential function with a base of \( e \) (Euler's number, approximately 2.718) raised to the power of \(-x\).- The expression \( e^{-x} - 5 \) implies that 5 is subtracted from the result of the exponential function. This function represents an exponential decay, shifted downwards by 5 units on a graph. Exploring its behavior graphically would show an exponential curve approaching -5 as \( x \) moves towards positive infinity.

We have the function as hx=e-x-5 We know that, for defining the function hx=e-x-5, x can take any of real values. Thus, Domain of the function hx=e-x-5 is x∈ℝ. For x∈ℝ, ex>0. Thus, Least value of hx=e-x-5 will be -5 as e-x>0. Therefore, Range of the function hx=e-x-5 is (-5,∞).Now, for plotting the graph of hx=e-x-5, first we have to took inverse of the function y=ex as we get y=e-x. Now we need to shift the graph of y=e-x 5 unit downward to obtain the graph hx=e-x-5.